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Solution - Absolute value equations

Exact form: x=-32,16
x=-\frac{3}{2} , \frac{1}{6}
Mixed number form: x=-112,16
x=-1\frac{1}{2} , \frac{1}{6}
Decimal form: x=1.5,0.167
x=-1.5 , 0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x2|=|4x+1|
without the absolute value bars:

|x|=|y||2x2|=|4x+1|
x=+y(2x2)=(4x+1)
x=y(2x2)=(4x+1)
+x=y(2x2)=(4x+1)
x=y(2x2)=(4x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x2|=|4x+1|
x=+y , +x=y(2x2)=(4x+1)
x=y , x=y(2x2)=(4x+1)

2. Solve the two equations for x

11 additional steps

(2x-2)=(4x+1)

Subtract from both sides:

(2x-2)-4x=(4x+1)-4x

Group like terms:

(2x-4x)-2=(4x+1)-4x

Simplify the arithmetic:

-2x-2=(4x+1)-4x

Group like terms:

-2x-2=(4x-4x)+1

Simplify the arithmetic:

2x2=1

Add to both sides:

(-2x-2)+2=1+2

Simplify the arithmetic:

2x=1+2

Simplify the arithmetic:

2x=3

Divide both sides by :

(-2x)-2=3-2

Cancel out the negatives:

2x2=3-2

Simplify the fraction:

x=3-2

Move the negative sign from the denominator to the numerator:

x=-32

10 additional steps

(2x-2)=-(4x+1)

Expand the parentheses:

(2x-2)=-4x-1

Add to both sides:

(2x-2)+4x=(-4x-1)+4x

Group like terms:

(2x+4x)-2=(-4x-1)+4x

Simplify the arithmetic:

6x-2=(-4x-1)+4x

Group like terms:

6x-2=(-4x+4x)-1

Simplify the arithmetic:

6x2=1

Add to both sides:

(6x-2)+2=-1+2

Simplify the arithmetic:

6x=1+2

Simplify the arithmetic:

6x=1

Divide both sides by :

(6x)6=16

Simplify the fraction:

x=16

3. List the solutions

x=-32,16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x2|
y=|4x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.