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Solution - Absolute value equations

Exact form: x=45,0
x=\frac{4}{5} , 0
Decimal form: x=0.8,0
x=0.8 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x2|=|3x+2|
without the absolute value bars:

|x|=|y||2x2|=|3x+2|
x=+y(2x2)=(3x+2)
x=y(2x2)=(3x+2)
+x=y(2x2)=(3x+2)
x=y(2x2)=(3x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x2|=|3x+2|
x=+y , +x=y(2x2)=(3x+2)
x=y , x=y(2x2)=(3x+2)

2. Solve the two equations for x

9 additional steps

(2x-2)=(-3x+2)

Add to both sides:

(2x-2)+3x=(-3x+2)+3x

Group like terms:

(2x+3x)-2=(-3x+2)+3x

Simplify the arithmetic:

5x-2=(-3x+2)+3x

Group like terms:

5x-2=(-3x+3x)+2

Simplify the arithmetic:

5x2=2

Add to both sides:

(5x-2)+2=2+2

Simplify the arithmetic:

5x=2+2

Simplify the arithmetic:

5x=4

Divide both sides by :

(5x)5=45

Simplify the fraction:

x=45

11 additional steps

(2x-2)=-(-3x+2)

Expand the parentheses:

(2x-2)=3x-2

Subtract from both sides:

(2x-2)-3x=(3x-2)-3x

Group like terms:

(2x-3x)-2=(3x-2)-3x

Simplify the arithmetic:

-x-2=(3x-2)-3x

Group like terms:

-x-2=(3x-3x)-2

Simplify the arithmetic:

x2=2

Add to both sides:

(-x-2)+2=-2+2

Simplify the arithmetic:

x=2+2

Simplify the arithmetic:

x=0

Multiply both sides by :

-x·-1=0·-1

Remove the one(s):

x=0·-1

Multiply by zero:

x=0

3. List the solutions

x=45,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x2|
y=|3x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.