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Solution - Absolute value equations

Exact form: x=-323,-67
x=-\frac{32}{3} , -\frac{6}{7}
Mixed number form: x=-1023,-67
x=-10\frac{2}{3} , -\frac{6}{7}
Decimal form: x=10.667,0.857
x=-10.667 , -0.857

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x13|=|5x+19|
without the absolute value bars:

|x|=|y||2x13|=|5x+19|
x=+y(2x13)=(5x+19)
x=y(2x13)=(5x+19)
+x=y(2x13)=(5x+19)
x=y(2x13)=(5x+19)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x13|=|5x+19|
x=+y , +x=y(2x13)=(5x+19)
x=y , x=y(2x13)=(5x+19)

2. Solve the two equations for x

11 additional steps

(2x-13)=(5x+19)

Subtract from both sides:

(2x-13)-5x=(5x+19)-5x

Group like terms:

(2x-5x)-13=(5x+19)-5x

Simplify the arithmetic:

-3x-13=(5x+19)-5x

Group like terms:

-3x-13=(5x-5x)+19

Simplify the arithmetic:

3x13=19

Add to both sides:

(-3x-13)+13=19+13

Simplify the arithmetic:

3x=19+13

Simplify the arithmetic:

3x=32

Divide both sides by :

(-3x)-3=32-3

Cancel out the negatives:

3x3=32-3

Simplify the fraction:

x=32-3

Move the negative sign from the denominator to the numerator:

x=-323

10 additional steps

(2x-13)=-(5x+19)

Expand the parentheses:

(2x-13)=-5x-19

Add to both sides:

(2x-13)+5x=(-5x-19)+5x

Group like terms:

(2x+5x)-13=(-5x-19)+5x

Simplify the arithmetic:

7x-13=(-5x-19)+5x

Group like terms:

7x-13=(-5x+5x)-19

Simplify the arithmetic:

7x13=19

Add to both sides:

(7x-13)+13=-19+13

Simplify the arithmetic:

7x=19+13

Simplify the arithmetic:

7x=6

Divide both sides by :

(7x)7=-67

Simplify the fraction:

x=-67

3. List the solutions

x=-323,-67
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x13|
y=|5x+19|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.