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Solution - Absolute value equations

Exact form: x=5
x=5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x11|=|2x9|
without the absolute value bars:

|x|=|y||2x11|=|2x9|
x=+y(2x11)=(2x9)
x=y(2x11)=(2x9)
+x=y(2x11)=(2x9)
x=y(2x11)=(2x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x11|=|2x9|
x=+y , +x=y(2x11)=(2x9)
x=y , x=y(2x11)=(2x9)

2. Solve the two equations for x

5 additional steps

(2x-11)=(2x-9)

Subtract from both sides:

(2x-11)-2x=(2x-9)-2x

Group like terms:

(2x-2x)-11=(2x-9)-2x

Simplify the arithmetic:

-11=(2x-9)-2x

Group like terms:

-11=(2x-2x)-9

Simplify the arithmetic:

11=9

The statement is false:

11=9

The equation is false so it has no solution.

12 additional steps

(2x-11)=-(2x-9)

Expand the parentheses:

(2x-11)=-2x+9

Add to both sides:

(2x-11)+2x=(-2x+9)+2x

Group like terms:

(2x+2x)-11=(-2x+9)+2x

Simplify the arithmetic:

4x-11=(-2x+9)+2x

Group like terms:

4x-11=(-2x+2x)+9

Simplify the arithmetic:

4x11=9

Add to both sides:

(4x-11)+11=9+11

Simplify the arithmetic:

4x=9+11

Simplify the arithmetic:

4x=20

Divide both sides by :

(4x)4=204

Simplify the fraction:

x=204

Find the greatest common factor of the numerator and denominator:

x=(5·4)(1·4)

Factor out and cancel the greatest common factor:

x=5

3. Graph

Each line represents the function of one side of the equation:
y=|2x11|
y=|2x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.