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Solution - Absolute value equations

Exact form: x=54
x=\frac{5}{4}
Mixed number form: x=114
x=1\frac{1}{4}
Decimal form: x=1.25
x=1.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x1|2|x2|=0

Add 2|x2| to both sides of the equation:

|2x1|2|x2|+2|x2|=2|x2|

Simplify the arithmetic

|2x1|=2|x2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=2|x2|
without the absolute value bars:

|x|=|y||2x1|=2|x2|
x=+y(2x1)=2(x2)
x=y(2x1)=2((x2))
+x=y(2x1)=2(x2)
x=y(2x1)=2(x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=2|x2|
x=+y , +x=y(2x1)=2(x2)
x=y , x=y(2x1)=2((x2))

3. Solve the two equations for x

7 additional steps

(2x-1)=2·(x-2)

Expand the parentheses:

(2x-1)=2x+2·-2

Simplify the arithmetic:

(2x-1)=2x-4

Subtract from both sides:

(2x-1)-2x=(2x-4)-2x

Group like terms:

(2x-2x)-1=(2x-4)-2x

Simplify the arithmetic:

-1=(2x-4)-2x

Group like terms:

-1=(2x-2x)-4

Simplify the arithmetic:

1=4

The statement is false:

1=4

The equation is false so it has no solution.

14 additional steps

(2x-1)=2·(-(x-2))

Expand the parentheses:

(2x-1)=2·(-x+2)

(2x-1)=2·-x+2·2

Group like terms:

(2x-1)=(2·-1)x+2·2

Multiply the coefficients:

(2x-1)=-2x+2·2

Simplify the arithmetic:

(2x-1)=-2x+4

Add to both sides:

(2x-1)+2x=(-2x+4)+2x

Group like terms:

(2x+2x)-1=(-2x+4)+2x

Simplify the arithmetic:

4x-1=(-2x+4)+2x

Group like terms:

4x-1=(-2x+2x)+4

Simplify the arithmetic:

4x1=4

Add to both sides:

(4x-1)+1=4+1

Simplify the arithmetic:

4x=4+1

Simplify the arithmetic:

4x=5

Divide both sides by :

(4x)4=54

Simplify the fraction:

x=54

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=2|x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.