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Solution - Absolute value equations

Exact form: x=-4,-25
x=-4 , -\frac{2}{5}
Decimal form: x=4,0.4
x=-4 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=3|x+1|
without the absolute value bars:

|x|=|y||2x1|=3|x+1|
x=+y(2x1)=3(x+1)
x=y(2x1)=3((x+1))
+x=y(2x1)=3(x+1)
x=y(2x1)=3(x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=3|x+1|
x=+y , +x=y(2x1)=3(x+1)
x=y , x=y(2x1)=3((x+1))

2. Solve the two equations for x

12 additional steps

(2x-1)=3·(x+1)

Expand the parentheses:

(2x-1)=3x+3·1

Simplify the arithmetic:

(2x-1)=3x+3

Subtract from both sides:

(2x-1)-3x=(3x+3)-3x

Group like terms:

(2x-3x)-1=(3x+3)-3x

Simplify the arithmetic:

-x-1=(3x+3)-3x

Group like terms:

-x-1=(3x-3x)+3

Simplify the arithmetic:

x1=3

Add to both sides:

(-x-1)+1=3+1

Simplify the arithmetic:

x=3+1

Simplify the arithmetic:

x=4

Multiply both sides by :

-x·-1=4·-1

Remove the one(s):

x=4·-1

Simplify the arithmetic:

x=4

14 additional steps

(2x-1)=3·(-(x+1))

Expand the parentheses:

(2x-1)=3·(-x-1)

(2x-1)=3·-x+3·-1

Group like terms:

(2x-1)=(3·-1)x+3·-1

Multiply the coefficients:

(2x-1)=-3x+3·-1

Simplify the arithmetic:

(2x-1)=-3x-3

Add to both sides:

(2x-1)+3x=(-3x-3)+3x

Group like terms:

(2x+3x)-1=(-3x-3)+3x

Simplify the arithmetic:

5x-1=(-3x-3)+3x

Group like terms:

5x-1=(-3x+3x)-3

Simplify the arithmetic:

5x1=3

Add to both sides:

(5x-1)+1=-3+1

Simplify the arithmetic:

5x=3+1

Simplify the arithmetic:

5x=2

Divide both sides by :

(5x)5=-25

Simplify the fraction:

x=-25

3. List the solutions

x=-4,-25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=3|x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.