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Solution - Absolute value equations

Exact form: x=-52,-12
x=-\frac{5}{2} , -\frac{1}{2}
Mixed number form: x=-212,-12
x=-2\frac{1}{2} , -\frac{1}{2}
Decimal form: x=2.5,0.5
x=-2.5 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=|4x+4|
without the absolute value bars:

|x|=|y||2x1|=|4x+4|
x=+y(2x1)=(4x+4)
x=y(2x1)=(4x+4)
+x=y(2x1)=(4x+4)
x=y(2x1)=(4x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=|4x+4|
x=+y , +x=y(2x1)=(4x+4)
x=y , x=y(2x1)=(4x+4)

2. Solve the two equations for x

11 additional steps

(2x-1)=(4x+4)

Subtract from both sides:

(2x-1)-4x=(4x+4)-4x

Group like terms:

(2x-4x)-1=(4x+4)-4x

Simplify the arithmetic:

-2x-1=(4x+4)-4x

Group like terms:

-2x-1=(4x-4x)+4

Simplify the arithmetic:

2x1=4

Add to both sides:

(-2x-1)+1=4+1

Simplify the arithmetic:

2x=4+1

Simplify the arithmetic:

2x=5

Divide both sides by :

(-2x)-2=5-2

Cancel out the negatives:

2x2=5-2

Simplify the fraction:

x=5-2

Move the negative sign from the denominator to the numerator:

x=-52

12 additional steps

(2x-1)=-(4x+4)

Expand the parentheses:

(2x-1)=-4x-4

Add to both sides:

(2x-1)+4x=(-4x-4)+4x

Group like terms:

(2x+4x)-1=(-4x-4)+4x

Simplify the arithmetic:

6x-1=(-4x-4)+4x

Group like terms:

6x-1=(-4x+4x)-4

Simplify the arithmetic:

6x1=4

Add to both sides:

(6x-1)+1=-4+1

Simplify the arithmetic:

6x=4+1

Simplify the arithmetic:

6x=3

Divide both sides by :

(6x)6=-36

Simplify the fraction:

x=-36

Find the greatest common factor of the numerator and denominator:

x=(-1·3)(2·3)

Factor out and cancel the greatest common factor:

x=-12

3. List the solutions

x=-52,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=|4x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.