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Solution - Absolute value equations

Exact form: x=-141,145
x=-\frac{1}{41} , \frac{1}{45}
Decimal form: x=0.024,0.022
x=-0.024 , 0.022

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=|43x|
without the absolute value bars:

|x|=|y||2x1|=|43x|
x=+y(2x1)=(43x)
x=y(2x1)=(43x)
+x=y(2x1)=(43x)
x=y(2x1)=(43x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=|43x|
x=+y , +x=y(2x1)=(43x)
x=y , x=y(2x1)=(43x)

2. Solve the two equations for x

10 additional steps

(2x-1)=43x

Subtract from both sides:

(2x-1)-43x=(43x)-43x

Group like terms:

(2x-43x)-1=(43x)-43x

Simplify the arithmetic:

-41x-1=(43x)-43x

Simplify the arithmetic:

41x1=0

Add to both sides:

(-41x-1)+1=0+1

Simplify the arithmetic:

41x=0+1

Simplify the arithmetic:

41x=1

Divide both sides by :

(-41x)-41=1-41

Cancel out the negatives:

41x41=1-41

Simplify the fraction:

x=1-41

Move the negative sign from the denominator to the numerator:

x=-141

7 additional steps

(2x-1)=-43x

Add to both sides:

(2x-1)+1=(-43x)+1

Simplify the arithmetic:

2x=(-43x)+1

Add to both sides:

(2x)+43x=((-43x)+1)+43x

Simplify the arithmetic:

45x=((-43x)+1)+43x

Group like terms:

45x=(-43x+43x)+1

Simplify the arithmetic:

45x=1

Divide both sides by :

(45x)45=145

Simplify the fraction:

x=145

3. List the solutions

x=-141,145
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=|43x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.