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Solution - Absolute value equations

Exact form: x=4,11
x=4 , 11

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=|4x+23|
without the absolute value bars:

|x|=|y||2x1|=|4x+23|
x=+y(2x1)=(4x+23)
x=y(2x1)=(4x+23)
+x=y(2x1)=(4x+23)
x=y(2x1)=(4x+23)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=|4x+23|
x=+y , +x=y(2x1)=(4x+23)
x=y , x=y(2x1)=(4x+23)

2. Solve the two equations for x

11 additional steps

(2x-1)=(-4x+23)

Add to both sides:

(2x-1)+4x=(-4x+23)+4x

Group like terms:

(2x+4x)-1=(-4x+23)+4x

Simplify the arithmetic:

6x-1=(-4x+23)+4x

Group like terms:

6x-1=(-4x+4x)+23

Simplify the arithmetic:

6x1=23

Add to both sides:

(6x-1)+1=23+1

Simplify the arithmetic:

6x=23+1

Simplify the arithmetic:

6x=24

Divide both sides by :

(6x)6=246

Simplify the fraction:

x=246

Find the greatest common factor of the numerator and denominator:

x=(4·6)(1·6)

Factor out and cancel the greatest common factor:

x=4

14 additional steps

(2x-1)=-(-4x+23)

Expand the parentheses:

(2x-1)=4x-23

Subtract from both sides:

(2x-1)-4x=(4x-23)-4x

Group like terms:

(2x-4x)-1=(4x-23)-4x

Simplify the arithmetic:

-2x-1=(4x-23)-4x

Group like terms:

-2x-1=(4x-4x)-23

Simplify the arithmetic:

2x1=23

Add to both sides:

(-2x-1)+1=-23+1

Simplify the arithmetic:

2x=23+1

Simplify the arithmetic:

2x=22

Divide both sides by :

(-2x)-2=-22-2

Cancel out the negatives:

2x2=-22-2

Simplify the fraction:

x=-22-2

Cancel out the negatives:

x=222

Find the greatest common factor of the numerator and denominator:

x=(11·2)(1·2)

Factor out and cancel the greatest common factor:

x=11

3. List the solutions

x=4,11
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=|4x+23|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.