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Solution - Absolute value equations

Exact form:

x = \frac{1}{3}, 0

x=\frac{1}{3} , 0

Decimal form:

x = 0.333, 0

x=0.333 , 0

See steps

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

$| 2 x - 1 | + | 4 x - 1 | = 0$

Add $- | 4 x - 1 |$ to both sides of the equation:

$| 2 x - 1 | + | 4 x - 1 | - | 4 x - 1 | = - | 4 x - 1 |$

Simplify the arithmetic

$| 2 x - 1 | = - | 4 x - 1 |$

2. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 x - 1 | = - | 4 x - 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 x - 1 \| = - \| 4 x - 1 \|$
$x = + y$	$(2 x - 1) = - (4 x - 1)$
$x = - y$	$(2 x - 1) = - - (4 x - 1)$
$+ x = y$	$(2 x - 1) = - (4 x - 1)$
$- x = y$	$- (2 x - 1) = - (4 x - 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 x - 1 \| = - \| 4 x - 1 \|$
$x = + y$ , $+ x = y$	$(2 x - 1) = - (4 x - 1)$
$x = - y$ , $- x = y$	$(2 x - 1) = - - (4 x - 1)$

3. Solve the two equations for x

12 additional steps

$(2 x - 1) = - (4 x - 1)$

Expand the parentheses:

$(2 x - 1) = - 4 x + 1$

Add to both sides:

$(2 x - 1) + 4 x = (- 4 x + 1) + 4 x$

Group like terms:

$(2 x + 4 x) - 1 = (- 4 x + 1) + 4 x$

Simplify the arithmetic:

$6 x - 1 = (- 4 x + 1) + 4 x$

Group like terms:

$6 x - 1 = (- 4 x + 4 x) + 1$

Simplify the arithmetic:

$6 x - 1 = 1$

Add to both sides:

$(6 x - 1) + 1 = 1 + 1$

Simplify the arithmetic:

$6 x = 1 + 1$

Simplify the arithmetic:

$6 x = 2$

Divide both sides by :

$\frac{(6 x)}{6} = \frac{2}{6}$

Simplify the fraction:

$x = \frac{2}{6}$

Find the greatest common factor of the numerator and denominator:

$x = \frac{(1 \cdot 2)}{(3 \cdot 2)}$

Factor out and cancel the greatest common factor:

$x = \frac{1}{3}$

9 additional steps

$(2 x - 1) = - (- (4 x - 1))$

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

$(2 x - 1) = 4 x - 1$

Subtract from both sides:

$(2 x - 1) - 4 x = (4 x - 1) - 4 x$

Group like terms:

$(2 x - 4 x) - 1 = (4 x - 1) - 4 x$

Simplify the arithmetic:

$- 2 x - 1 = (4 x - 1) - 4 x$

Group like terms:

$- 2 x - 1 = (4 x - 4 x) - 1$

Simplify the arithmetic:

$- 2 x - 1 = - 1$

Add to both sides:

$(- 2 x - 1) + 1 = - 1 + 1$

Simplify the arithmetic:

$- 2 x = - 1 + 1$

Simplify the arithmetic:

$- 2 x = 0$

Divide both sides by the coefficient:

$x = 0$

4. List the solutions

$x = \frac{1}{3}, 0$
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
$y = | 2 x - 1 |$
$y = - | 4 x - 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved