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Solution - Absolute value equations

Exact form: x=2,53
x=2 , \frac{5}{3}
Mixed number form: x=2,123
x=2 , 1\frac{2}{3}
Decimal form: x=2,1.667
x=2 , 1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x3|=|4x7|
without the absolute value bars:

|x|=|y||2x3|=|4x7|
x=+y(2x3)=(4x7)
x=y(2x3)=(4x7)
+x=y(2x3)=(4x7)
x=y(2x3)=(4x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x3|=|4x7|
x=+y , +x=y(2x3)=(4x7)
x=y , x=y(2x3)=(4x7)

2. Solve the two equations for x

13 additional steps

(2x-3)=(4x-7)

Subtract from both sides:

(2x-3)-4x=(4x-7)-4x

Group like terms:

(2x-4x)-3=(4x-7)-4x

Simplify the arithmetic:

-2x-3=(4x-7)-4x

Group like terms:

-2x-3=(4x-4x)-7

Simplify the arithmetic:

2x3=7

Add to both sides:

(-2x-3)+3=-7+3

Simplify the arithmetic:

2x=7+3

Simplify the arithmetic:

2x=4

Divide both sides by :

(-2x)-2=-4-2

Cancel out the negatives:

2x2=-4-2

Simplify the fraction:

x=-4-2

Cancel out the negatives:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(2x-3)=-(4x-7)

Expand the parentheses:

(2x-3)=-4x+7

Add to both sides:

(2x-3)+4x=(-4x+7)+4x

Group like terms:

(2x+4x)-3=(-4x+7)+4x

Simplify the arithmetic:

6x-3=(-4x+7)+4x

Group like terms:

6x-3=(-4x+4x)+7

Simplify the arithmetic:

6x3=7

Add to both sides:

(6x-3)+3=7+3

Simplify the arithmetic:

6x=7+3

Simplify the arithmetic:

6x=10

Divide both sides by :

(6x)6=106

Simplify the fraction:

x=106

Find the greatest common factor of the numerator and denominator:

x=(5·2)(3·2)

Factor out and cancel the greatest common factor:

x=53

3. List the solutions

x=2,53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x3|
y=|4x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.