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Solution - Absolute value equations

Exact form: x=83,-6
x=\frac{8}{3} , -6
Mixed number form: x=223,-6
x=2\frac{2}{3} , -6
Decimal form: x=2.667,6
x=2.667 , -6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x1|+|x7|=0

Add |x7| to both sides of the equation:

|2x1|+|x7||x7|=|x7|

Simplify the arithmetic

|2x1|=|x7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x1|=|x7|
without the absolute value bars:

|x|=|y||2x1|=|x7|
x=+y(2x1)=(x7)
x=y(2x1)=(x7)
+x=y(2x1)=(x7)
x=y(2x1)=(x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x1|=|x7|
x=+y , +x=y(2x1)=(x7)
x=y , x=y(2x1)=(x7)

3. Solve the two equations for x

10 additional steps

(2x-1)=-(x-7)

Expand the parentheses:

(2x-1)=-x+7

Add to both sides:

(2x-1)+x=(-x+7)+x

Group like terms:

(2x+x)-1=(-x+7)+x

Simplify the arithmetic:

3x-1=(-x+7)+x

Group like terms:

3x-1=(-x+x)+7

Simplify the arithmetic:

3x1=7

Add to both sides:

(3x-1)+1=7+1

Simplify the arithmetic:

3x=7+1

Simplify the arithmetic:

3x=8

Divide both sides by :

(3x)3=83

Simplify the fraction:

x=83

8 additional steps

(2x-1)=-(-(x-7))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x-1)=x-7

Subtract from both sides:

(2x-1)-x=(x-7)-x

Group like terms:

(2x-x)-1=(x-7)-x

Simplify the arithmetic:

x-1=(x-7)-x

Group like terms:

x-1=(x-x)-7

Simplify the arithmetic:

x1=7

Add to both sides:

(x-1)+1=-7+1

Simplify the arithmetic:

x=7+1

Simplify the arithmetic:

x=6

4. List the solutions

x=83,-6
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x1|
y=|x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.