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Solution - Absolute value equations

Exact form: x=-23,1
x=-\frac{2}{3} , 1
Decimal form: x=0.667,1
x=-0.667 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x+8|+|10x|=0

Add |10x| to both sides of the equation:

|2x+8|+|10x||10x|=|10x|

Simplify the arithmetic

|2x+8|=|10x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+8|=|10x|
without the absolute value bars:

|x|=|y||2x+8|=|10x|
x=+y(2x+8)=(10x)
x=y(2x+8)=(10x)
+x=y(2x+8)=(10x)
x=y(2x+8)=(10x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+8|=|10x|
x=+y , +x=y(2x+8)=(10x)
x=y , x=y(2x+8)=(10x)

3. Solve the two equations for x

9 additional steps

(2x+8)=-10x

Subtract from both sides:

(2x+8)-8=(-10x)-8

Simplify the arithmetic:

2x=(-10x)-8

Add to both sides:

(2x)+10x=((-10x)-8)+10x

Simplify the arithmetic:

12x=((-10x)-8)+10x

Group like terms:

12x=(-10x+10x)-8

Simplify the arithmetic:

12x=8

Divide both sides by :

(12x)12=-812

Simplify the fraction:

x=-812

Find the greatest common factor of the numerator and denominator:

x=(-2·4)(3·4)

Factor out and cancel the greatest common factor:

x=-23

13 additional steps

(2x+8)=--10x

Group like terms:

(2x+8)=(-1·-10)x

Multiply the coefficients:

(2x+8)=10x

Subtract from both sides:

(2x+8)-10x=(10x)-10x

Group like terms:

(2x-10x)+8=(10x)-10x

Simplify the arithmetic:

-8x+8=(10x)-10x

Simplify the arithmetic:

8x+8=0

Subtract from both sides:

(-8x+8)-8=0-8

Simplify the arithmetic:

8x=08

Simplify the arithmetic:

8x=8

Divide both sides by :

(-8x)-8=-8-8

Cancel out the negatives:

8x8=-8-8

Simplify the fraction:

x=-8-8

Cancel out the negatives:

x=88

Simplify the fraction:

x=1

4. List the solutions

x=-23,1
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x+8|
y=|10x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.