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Solution - Absolute value equations

Exact form: x=-14,3
x=-\frac{1}{4} , 3
Decimal form: x=0.25,3
x=-0.25 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+7|=|6x+5|
without the absolute value bars:

|x|=|y||2x+7|=|6x+5|
x=+y(2x+7)=(6x+5)
x=y(2x+7)=(6x+5)
+x=y(2x+7)=(6x+5)
x=y(2x+7)=(6x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+7|=|6x+5|
x=+y , +x=y(2x+7)=(6x+5)
x=y , x=y(2x+7)=(6x+5)

2. Solve the two equations for x

11 additional steps

(2x+7)=(-6x+5)

Add to both sides:

(2x+7)+6x=(-6x+5)+6x

Group like terms:

(2x+6x)+7=(-6x+5)+6x

Simplify the arithmetic:

8x+7=(-6x+5)+6x

Group like terms:

8x+7=(-6x+6x)+5

Simplify the arithmetic:

8x+7=5

Subtract from both sides:

(8x+7)-7=5-7

Simplify the arithmetic:

8x=57

Simplify the arithmetic:

8x=2

Divide both sides by :

(8x)8=-28

Simplify the fraction:

x=-28

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(4·2)

Factor out and cancel the greatest common factor:

x=-14

14 additional steps

(2x+7)=-(-6x+5)

Expand the parentheses:

(2x+7)=6x-5

Subtract from both sides:

(2x+7)-6x=(6x-5)-6x

Group like terms:

(2x-6x)+7=(6x-5)-6x

Simplify the arithmetic:

-4x+7=(6x-5)-6x

Group like terms:

-4x+7=(6x-6x)-5

Simplify the arithmetic:

4x+7=5

Subtract from both sides:

(-4x+7)-7=-5-7

Simplify the arithmetic:

4x=57

Simplify the arithmetic:

4x=12

Divide both sides by :

(-4x)-4=-12-4

Cancel out the negatives:

4x4=-12-4

Simplify the fraction:

x=-12-4

Cancel out the negatives:

x=124

Find the greatest common factor of the numerator and denominator:

x=(3·4)(1·4)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=-14,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+7|
y=|6x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.