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Solution - Absolute value equations

Exact form: x=-12,-52
x=-\frac{1}{2} , -\frac{5}{2}
Mixed number form: x=-12,-212
x=-\frac{1}{2} , -2\frac{1}{2}
Decimal form: x=0.5,2.5
x=-0.5 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+7|=|4x+8|
without the absolute value bars:

|x|=|y||2x+7|=|4x+8|
x=+y(2x+7)=(4x+8)
x=y(2x+7)=(4x+8)
+x=y(2x+7)=(4x+8)
x=y(2x+7)=(4x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+7|=|4x+8|
x=+y , +x=y(2x+7)=(4x+8)
x=y , x=y(2x+7)=(4x+8)

2. Solve the two equations for x

11 additional steps

(2x+7)=(4x+8)

Subtract from both sides:

(2x+7)-4x=(4x+8)-4x

Group like terms:

(2x-4x)+7=(4x+8)-4x

Simplify the arithmetic:

-2x+7=(4x+8)-4x

Group like terms:

-2x+7=(4x-4x)+8

Simplify the arithmetic:

2x+7=8

Subtract from both sides:

(-2x+7)-7=8-7

Simplify the arithmetic:

2x=87

Simplify the arithmetic:

2x=1

Divide both sides by :

(-2x)-2=1-2

Cancel out the negatives:

2x2=1-2

Simplify the fraction:

x=1-2

Move the negative sign from the denominator to the numerator:

x=-12

12 additional steps

(2x+7)=-(4x+8)

Expand the parentheses:

(2x+7)=-4x-8

Add to both sides:

(2x+7)+4x=(-4x-8)+4x

Group like terms:

(2x+4x)+7=(-4x-8)+4x

Simplify the arithmetic:

6x+7=(-4x-8)+4x

Group like terms:

6x+7=(-4x+4x)-8

Simplify the arithmetic:

6x+7=8

Subtract from both sides:

(6x+7)-7=-8-7

Simplify the arithmetic:

6x=87

Simplify the arithmetic:

6x=15

Divide both sides by :

(6x)6=-156

Simplify the fraction:

x=-156

Find the greatest common factor of the numerator and denominator:

x=(-5·3)(2·3)

Factor out and cancel the greatest common factor:

x=-52

3. List the solutions

x=-12,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+7|
y=|4x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.