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Solution - Absolute value equations

Exact form: x=-6,-185
x=-6 , -\frac{18}{5}
Mixed number form: x=-6,-335
x=-6 , -3\frac{3}{5}
Decimal form: x=6,3.6
x=-6 , -3.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x+6||3x+12|=0

Add |3x+12| to both sides of the equation:

|2x+6||3x+12|+|3x+12|=|3x+12|

Simplify the arithmetic

|2x+6|=|3x+12|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+6|=|3x+12|
without the absolute value bars:

|x|=|y||2x+6|=|3x+12|
x=+y(2x+6)=(3x+12)
x=y(2x+6)=((3x+12))
+x=y(2x+6)=(3x+12)
x=y(2x+6)=(3x+12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+6|=|3x+12|
x=+y , +x=y(2x+6)=(3x+12)
x=y , x=y(2x+6)=((3x+12))

3. Solve the two equations for x

10 additional steps

(2x+6)=(3x+12)

Subtract from both sides:

(2x+6)-3x=(3x+12)-3x

Group like terms:

(2x-3x)+6=(3x+12)-3x

Simplify the arithmetic:

-x+6=(3x+12)-3x

Group like terms:

-x+6=(3x-3x)+12

Simplify the arithmetic:

x+6=12

Subtract from both sides:

(-x+6)-6=12-6

Simplify the arithmetic:

x=126

Simplify the arithmetic:

x=6

Multiply both sides by :

-x·-1=6·-1

Remove the one(s):

x=6·-1

Simplify the arithmetic:

x=6

10 additional steps

(2x+6)=-(3x+12)

Expand the parentheses:

(2x+6)=-3x-12

Add to both sides:

(2x+6)+3x=(-3x-12)+3x

Group like terms:

(2x+3x)+6=(-3x-12)+3x

Simplify the arithmetic:

5x+6=(-3x-12)+3x

Group like terms:

5x+6=(-3x+3x)-12

Simplify the arithmetic:

5x+6=12

Subtract from both sides:

(5x+6)-6=-12-6

Simplify the arithmetic:

5x=126

Simplify the arithmetic:

5x=18

Divide both sides by :

(5x)5=-185

Simplify the fraction:

x=-185

4. List the solutions

x=-6,-185
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x+6|
y=|3x+12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.