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Solution - Absolute value equations

Exact form: x=3,-37
x=3 , -\frac{3}{7}
Decimal form: x=3,0.429
x=3 , -0.429

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+6|=|5x3|
without the absolute value bars:

|x|=|y||2x+6|=|5x3|
x=+y(2x+6)=(5x3)
x=y(2x+6)=(5x3)
+x=y(2x+6)=(5x3)
x=y(2x+6)=(5x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+6|=|5x3|
x=+y , +x=y(2x+6)=(5x3)
x=y , x=y(2x+6)=(5x3)

2. Solve the two equations for x

13 additional steps

(2x+6)=(5x-3)

Subtract from both sides:

(2x+6)-5x=(5x-3)-5x

Group like terms:

(2x-5x)+6=(5x-3)-5x

Simplify the arithmetic:

-3x+6=(5x-3)-5x

Group like terms:

-3x+6=(5x-5x)-3

Simplify the arithmetic:

3x+6=3

Subtract from both sides:

(-3x+6)-6=-3-6

Simplify the arithmetic:

3x=36

Simplify the arithmetic:

3x=9

Divide both sides by :

(-3x)-3=-9-3

Cancel out the negatives:

3x3=-9-3

Simplify the fraction:

x=-9-3

Cancel out the negatives:

x=93

Find the greatest common factor of the numerator and denominator:

x=(3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

10 additional steps

(2x+6)=-(5x-3)

Expand the parentheses:

(2x+6)=-5x+3

Add to both sides:

(2x+6)+5x=(-5x+3)+5x

Group like terms:

(2x+5x)+6=(-5x+3)+5x

Simplify the arithmetic:

7x+6=(-5x+3)+5x

Group like terms:

7x+6=(-5x+5x)+3

Simplify the arithmetic:

7x+6=3

Subtract from both sides:

(7x+6)-6=3-6

Simplify the arithmetic:

7x=36

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=-37

Simplify the fraction:

x=-37

3. List the solutions

x=3,-37
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+6|
y=|5x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.