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Solution - Absolute value equations

Exact form: x=32,-32
x=\frac{3}{2} , -\frac{3}{2}
Mixed number form: x=112,-112
x=1\frac{1}{2} , -1\frac{1}{2}
Decimal form: x=1.5,1.5
x=1.5 , -1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+6|=|4x+3|
without the absolute value bars:

|x|=|y||2x+6|=|4x+3|
x=+y(2x+6)=(4x+3)
x=y(2x+6)=(4x+3)
+x=y(2x+6)=(4x+3)
x=y(2x+6)=(4x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+6|=|4x+3|
x=+y , +x=y(2x+6)=(4x+3)
x=y , x=y(2x+6)=(4x+3)

2. Solve the two equations for x

11 additional steps

(2x+6)=(4x+3)

Subtract from both sides:

(2x+6)-4x=(4x+3)-4x

Group like terms:

(2x-4x)+6=(4x+3)-4x

Simplify the arithmetic:

-2x+6=(4x+3)-4x

Group like terms:

-2x+6=(4x-4x)+3

Simplify the arithmetic:

2x+6=3

Subtract from both sides:

(-2x+6)-6=3-6

Simplify the arithmetic:

2x=36

Simplify the arithmetic:

2x=3

Divide both sides by :

(-2x)-2=-3-2

Cancel out the negatives:

2x2=-3-2

Simplify the fraction:

x=-3-2

Cancel out the negatives:

x=32

12 additional steps

(2x+6)=-(4x+3)

Expand the parentheses:

(2x+6)=-4x-3

Add to both sides:

(2x+6)+4x=(-4x-3)+4x

Group like terms:

(2x+4x)+6=(-4x-3)+4x

Simplify the arithmetic:

6x+6=(-4x-3)+4x

Group like terms:

6x+6=(-4x+4x)-3

Simplify the arithmetic:

6x+6=3

Subtract from both sides:

(6x+6)-6=-3-6

Simplify the arithmetic:

6x=36

Simplify the arithmetic:

6x=9

Divide both sides by :

(6x)6=-96

Simplify the fraction:

x=-96

Find the greatest common factor of the numerator and denominator:

x=(-3·3)(2·3)

Factor out and cancel the greatest common factor:

x=-32

3. List the solutions

x=32,-32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+6|
y=|4x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.