Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-94
x=-\frac{9}{4}
Mixed number form: x=-214
x=-2\frac{1}{4}
Decimal form: x=2.25
x=-2.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+6|=|2x3|
without the absolute value bars:

|x|=|y||2x+6|=|2x3|
x=+y(2x+6)=(2x3)
x=y(2x+6)=(2x3)
+x=y(2x+6)=(2x3)
x=y(2x+6)=(2x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+6|=|2x3|
x=+y , +x=y(2x+6)=(2x3)
x=y , x=y(2x+6)=(2x3)

2. Solve the two equations for x

9 additional steps

(2x+6)=(-2x-3)

Add to both sides:

(2x+6)+2x=(-2x-3)+2x

Group like terms:

(2x+2x)+6=(-2x-3)+2x

Simplify the arithmetic:

4x+6=(-2x-3)+2x

Group like terms:

4x+6=(-2x+2x)-3

Simplify the arithmetic:

4x+6=3

Subtract from both sides:

(4x+6)-6=-3-6

Simplify the arithmetic:

4x=36

Simplify the arithmetic:

4x=9

Divide both sides by :

(4x)4=-94

Simplify the fraction:

x=-94

6 additional steps

(2x+6)=-(-2x-3)

Expand the parentheses:

(2x+6)=2x+3

Subtract from both sides:

(2x+6)-2x=(2x+3)-2x

Group like terms:

(2x-2x)+6=(2x+3)-2x

Simplify the arithmetic:

6=(2x+3)-2x

Group like terms:

6=(2x-2x)+3

Simplify the arithmetic:

6=3

The statement is false:

6=3

The equation is false so it has no solution.

3. List the solutions

x=-94
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+6|
y=|2x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.