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Solution - Absolute value equations

Exact form: x=-57,-1511
x=-\frac{5}{7} , -\frac{15}{11}
Mixed number form: x=-57,-1411
x=-\frac{5}{7} , -1\frac{4}{11}
Decimal form: x=0.714,1.364
x=-0.714 , -1.364

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+5|=|9x+10|
without the absolute value bars:

|x|=|y||2x+5|=|9x+10|
x=+y(2x+5)=(9x+10)
x=y(2x+5)=(9x+10)
+x=y(2x+5)=(9x+10)
x=y(2x+5)=(9x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+5|=|9x+10|
x=+y , +x=y(2x+5)=(9x+10)
x=y , x=y(2x+5)=(9x+10)

2. Solve the two equations for x

11 additional steps

(2x+5)=(9x+10)

Subtract from both sides:

(2x+5)-9x=(9x+10)-9x

Group like terms:

(2x-9x)+5=(9x+10)-9x

Simplify the arithmetic:

-7x+5=(9x+10)-9x

Group like terms:

-7x+5=(9x-9x)+10

Simplify the arithmetic:

7x+5=10

Subtract from both sides:

(-7x+5)-5=10-5

Simplify the arithmetic:

7x=105

Simplify the arithmetic:

7x=5

Divide both sides by :

(-7x)-7=5-7

Cancel out the negatives:

7x7=5-7

Simplify the fraction:

x=5-7

Move the negative sign from the denominator to the numerator:

x=-57

10 additional steps

(2x+5)=-(9x+10)

Expand the parentheses:

(2x+5)=-9x-10

Add to both sides:

(2x+5)+9x=(-9x-10)+9x

Group like terms:

(2x+9x)+5=(-9x-10)+9x

Simplify the arithmetic:

11x+5=(-9x-10)+9x

Group like terms:

11x+5=(-9x+9x)-10

Simplify the arithmetic:

11x+5=10

Subtract from both sides:

(11x+5)-5=-10-5

Simplify the arithmetic:

11x=105

Simplify the arithmetic:

11x=15

Divide both sides by :

(11x)11=-1511

Simplify the fraction:

x=-1511

3. List the solutions

x=-57,-1511
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+5|
y=|9x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.