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Solution - Absolute value equations

Exact form: x=34,-116
x=\frac{3}{4} , -\frac{1}{16}
Decimal form: x=0.75,0.062
x=0.75 , -0.062

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+5|=|14x4|
without the absolute value bars:

|x|=|y||2x+5|=|14x4|
x=+y(2x+5)=(14x4)
x=y(2x+5)=(14x4)
+x=y(2x+5)=(14x4)
x=y(2x+5)=(14x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+5|=|14x4|
x=+y , +x=y(2x+5)=(14x4)
x=y , x=y(2x+5)=(14x4)

2. Solve the two equations for x

13 additional steps

(2x+5)=(14x-4)

Subtract from both sides:

(2x+5)-14x=(14x-4)-14x

Group like terms:

(2x-14x)+5=(14x-4)-14x

Simplify the arithmetic:

-12x+5=(14x-4)-14x

Group like terms:

-12x+5=(14x-14x)-4

Simplify the arithmetic:

12x+5=4

Subtract from both sides:

(-12x+5)-5=-4-5

Simplify the arithmetic:

12x=45

Simplify the arithmetic:

12x=9

Divide both sides by :

(-12x)-12=-9-12

Cancel out the negatives:

12x12=-9-12

Simplify the fraction:

x=-9-12

Cancel out the negatives:

x=912

Find the greatest common factor of the numerator and denominator:

x=(3·3)(4·3)

Factor out and cancel the greatest common factor:

x=34

10 additional steps

(2x+5)=-(14x-4)

Expand the parentheses:

(2x+5)=-14x+4

Add to both sides:

(2x+5)+14x=(-14x+4)+14x

Group like terms:

(2x+14x)+5=(-14x+4)+14x

Simplify the arithmetic:

16x+5=(-14x+4)+14x

Group like terms:

16x+5=(-14x+14x)+4

Simplify the arithmetic:

16x+5=4

Subtract from both sides:

(16x+5)-5=4-5

Simplify the arithmetic:

16x=45

Simplify the arithmetic:

16x=1

Divide both sides by :

(16x)16=-116

Simplify the fraction:

x=-116

3. List the solutions

x=34,-116
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+5|
y=|14x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.