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Solution - Absolute value equations

Exact form: x=119,-120
x=\frac{1}{19} , -\frac{1}{20}
Decimal form: x=0.053,0.05
x=0.053 , -0.05

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+4|=|78x|
without the absolute value bars:

|x|=|y||2x+4|=|78x|
x=+y(2x+4)=(78x)
x=y(2x+4)=(78x)
+x=y(2x+4)=(78x)
x=y(2x+4)=(78x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+4|=|78x|
x=+y , +x=y(2x+4)=(78x)
x=y , x=y(2x+4)=(78x)

2. Solve the two equations for x

12 additional steps

(2x+4)=78x

Subtract from both sides:

(2x+4)-78x=(78x)-78x

Group like terms:

(2x-78x)+4=(78x)-78x

Simplify the arithmetic:

-76x+4=(78x)-78x

Simplify the arithmetic:

76x+4=0

Subtract from both sides:

(-76x+4)-4=0-4

Simplify the arithmetic:

76x=04

Simplify the arithmetic:

76x=4

Divide both sides by :

(-76x)-76=-4-76

Cancel out the negatives:

76x76=-4-76

Simplify the fraction:

x=-4-76

Cancel out the negatives:

x=476

Find the greatest common factor of the numerator and denominator:

x=(1·4)(19·4)

Factor out and cancel the greatest common factor:

x=119

9 additional steps

(2x+4)=-78x

Subtract from both sides:

(2x+4)-4=(-78x)-4

Simplify the arithmetic:

2x=(-78x)-4

Add to both sides:

(2x)+78x=((-78x)-4)+78x

Simplify the arithmetic:

80x=((-78x)-4)+78x

Group like terms:

80x=(-78x+78x)-4

Simplify the arithmetic:

80x=4

Divide both sides by :

(80x)80=-480

Simplify the fraction:

x=-480

Find the greatest common factor of the numerator and denominator:

x=(-1·4)(20·4)

Factor out and cancel the greatest common factor:

x=-120

3. List the solutions

x=119,-120
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+4|
y=|78x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.