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Solution - Absolute value equations

Exact form: x=15,95
x=15 , \frac{9}{5}
Mixed number form: x=15,145
x=15 , 1\frac{4}{5}
Decimal form: x=15,1.8
x=15 , 1.8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=|3x12|
without the absolute value bars:

|x|=|y||2x+3|=|3x12|
x=+y(2x+3)=(3x12)
x=y(2x+3)=(3x12)
+x=y(2x+3)=(3x12)
x=y(2x+3)=(3x12)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=|3x12|
x=+y , +x=y(2x+3)=(3x12)
x=y , x=y(2x+3)=(3x12)

2. Solve the two equations for x

10 additional steps

(2x+3)=(3x-12)

Subtract from both sides:

(2x+3)-3x=(3x-12)-3x

Group like terms:

(2x-3x)+3=(3x-12)-3x

Simplify the arithmetic:

-x+3=(3x-12)-3x

Group like terms:

-x+3=(3x-3x)-12

Simplify the arithmetic:

x+3=12

Subtract from both sides:

(-x+3)-3=-12-3

Simplify the arithmetic:

x=123

Simplify the arithmetic:

x=15

Multiply both sides by :

-x·-1=-15·-1

Remove the one(s):

x=-15·-1

Simplify the arithmetic:

x=15

10 additional steps

(2x+3)=-(3x-12)

Expand the parentheses:

(2x+3)=-3x+12

Add to both sides:

(2x+3)+3x=(-3x+12)+3x

Group like terms:

(2x+3x)+3=(-3x+12)+3x

Simplify the arithmetic:

5x+3=(-3x+12)+3x

Group like terms:

5x+3=(-3x+3x)+12

Simplify the arithmetic:

5x+3=12

Subtract from both sides:

(5x+3)-3=12-3

Simplify the arithmetic:

5x=123

Simplify the arithmetic:

5x=9

Divide both sides by :

(5x)5=95

Simplify the fraction:

x=95

3. List the solutions

x=15,95
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=|3x12|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.