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Solution - Absolute value equations

Exact form: x=53,-17
x=\frac{5}{3} , -\frac{1}{7}
Mixed number form: x=123,-17
x=1\frac{2}{3} , -\frac{1}{7}
Decimal form: x=1.667,0.143
x=1.667 , -0.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=|5x2|
without the absolute value bars:

|x|=|y||2x+3|=|5x2|
x=+y(2x+3)=(5x2)
x=y(2x+3)=(5x2)
+x=y(2x+3)=(5x2)
x=y(2x+3)=(5x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=|5x2|
x=+y , +x=y(2x+3)=(5x2)
x=y , x=y(2x+3)=(5x2)

2. Solve the two equations for x

11 additional steps

(2x+3)=(5x-2)

Subtract from both sides:

(2x+3)-5x=(5x-2)-5x

Group like terms:

(2x-5x)+3=(5x-2)-5x

Simplify the arithmetic:

-3x+3=(5x-2)-5x

Group like terms:

-3x+3=(5x-5x)-2

Simplify the arithmetic:

3x+3=2

Subtract from both sides:

(-3x+3)-3=-2-3

Simplify the arithmetic:

3x=23

Simplify the arithmetic:

3x=5

Divide both sides by :

(-3x)-3=-5-3

Cancel out the negatives:

3x3=-5-3

Simplify the fraction:

x=-5-3

Cancel out the negatives:

x=53

10 additional steps

(2x+3)=-(5x-2)

Expand the parentheses:

(2x+3)=-5x+2

Add to both sides:

(2x+3)+5x=(-5x+2)+5x

Group like terms:

(2x+5x)+3=(-5x+2)+5x

Simplify the arithmetic:

7x+3=(-5x+2)+5x

Group like terms:

7x+3=(-5x+5x)+2

Simplify the arithmetic:

7x+3=2

Subtract from both sides:

(7x+3)-3=2-3

Simplify the arithmetic:

7x=23

Simplify the arithmetic:

7x=1

Divide both sides by :

(7x)7=-17

Simplify the fraction:

x=-17

3. List the solutions

x=53,-17
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=|5x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.