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Solution - Absolute value equations

Exact form: x=-27,43
x=-\frac{2}{7} , \frac{4}{3}
Mixed number form: x=-27,113
x=-\frac{2}{7} , 1\frac{1}{3}
Decimal form: x=0.286,1.333
x=-0.286 , 1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=|5x+1|
without the absolute value bars:

|x|=|y||2x+3|=|5x+1|
x=+y(2x+3)=(5x+1)
x=y(2x+3)=(5x+1)
+x=y(2x+3)=(5x+1)
x=y(2x+3)=(5x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=|5x+1|
x=+y , +x=y(2x+3)=(5x+1)
x=y , x=y(2x+3)=(5x+1)

2. Solve the two equations for x

9 additional steps

(2x+3)=(-5x+1)

Add to both sides:

(2x+3)+5x=(-5x+1)+5x

Group like terms:

(2x+5x)+3=(-5x+1)+5x

Simplify the arithmetic:

7x+3=(-5x+1)+5x

Group like terms:

7x+3=(-5x+5x)+1

Simplify the arithmetic:

7x+3=1

Subtract from both sides:

(7x+3)-3=1-3

Simplify the arithmetic:

7x=13

Simplify the arithmetic:

7x=2

Divide both sides by :

(7x)7=-27

Simplify the fraction:

x=-27

12 additional steps

(2x+3)=-(-5x+1)

Expand the parentheses:

(2x+3)=5x-1

Subtract from both sides:

(2x+3)-5x=(5x-1)-5x

Group like terms:

(2x-5x)+3=(5x-1)-5x

Simplify the arithmetic:

-3x+3=(5x-1)-5x

Group like terms:

-3x+3=(5x-5x)-1

Simplify the arithmetic:

3x+3=1

Subtract from both sides:

(-3x+3)-3=-1-3

Simplify the arithmetic:

3x=13

Simplify the arithmetic:

3x=4

Divide both sides by :

(-3x)-3=-4-3

Cancel out the negatives:

3x3=-4-3

Simplify the fraction:

x=-4-3

Cancel out the negatives:

x=43

3. List the solutions

x=-27,43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=|5x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.