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Solution - Absolute value equations

Exact form: x=32,14
x=\frac{3}{2} , \frac{1}{4}
Mixed number form: x=112,14
x=1\frac{1}{2} , \frac{1}{4}
Decimal form: x=1.5,0.25
x=1.5 , 0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+2|=|6x4|
without the absolute value bars:

|x|=|y||2x+2|=|6x4|
x=+y(2x+2)=(6x4)
x=y(2x+2)=(6x4)
+x=y(2x+2)=(6x4)
x=y(2x+2)=(6x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+2|=|6x4|
x=+y , +x=y(2x+2)=(6x4)
x=y , x=y(2x+2)=(6x4)

2. Solve the two equations for x

13 additional steps

(2x+2)=(6x-4)

Subtract from both sides:

(2x+2)-6x=(6x-4)-6x

Group like terms:

(2x-6x)+2=(6x-4)-6x

Simplify the arithmetic:

-4x+2=(6x-4)-6x

Group like terms:

-4x+2=(6x-6x)-4

Simplify the arithmetic:

4x+2=4

Subtract from both sides:

(-4x+2)-2=-4-2

Simplify the arithmetic:

4x=42

Simplify the arithmetic:

4x=6

Divide both sides by :

(-4x)-4=-6-4

Cancel out the negatives:

4x4=-6-4

Simplify the fraction:

x=-6-4

Cancel out the negatives:

x=64

Find the greatest common factor of the numerator and denominator:

x=(3·2)(2·2)

Factor out and cancel the greatest common factor:

x=32

12 additional steps

(2x+2)=-(6x-4)

Expand the parentheses:

(2x+2)=-6x+4

Add to both sides:

(2x+2)+6x=(-6x+4)+6x

Group like terms:

(2x+6x)+2=(-6x+4)+6x

Simplify the arithmetic:

8x+2=(-6x+4)+6x

Group like terms:

8x+2=(-6x+6x)+4

Simplify the arithmetic:

8x+2=4

Subtract from both sides:

(8x+2)-2=4-2

Simplify the arithmetic:

8x=42

Simplify the arithmetic:

8x=2

Divide both sides by :

(8x)8=28

Simplify the fraction:

x=28

Find the greatest common factor of the numerator and denominator:

x=(1·2)(4·2)

Factor out and cancel the greatest common factor:

x=14

3. List the solutions

x=32,14
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+2|
y=|6x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.