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Solution - Absolute value equations

Exact form: x=2,27
x=2 , \frac{2}{7}
Decimal form: x=2,0.286
x=2 , 0.286

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+2|=|5x4|
without the absolute value bars:

|x|=|y||2x+2|=|5x4|
x=+y(2x+2)=(5x4)
x=y(2x+2)=(5x4)
+x=y(2x+2)=(5x4)
x=y(2x+2)=(5x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+2|=|5x4|
x=+y , +x=y(2x+2)=(5x4)
x=y , x=y(2x+2)=(5x4)

2. Solve the two equations for x

13 additional steps

(2x+2)=(5x-4)

Subtract from both sides:

(2x+2)-5x=(5x-4)-5x

Group like terms:

(2x-5x)+2=(5x-4)-5x

Simplify the arithmetic:

-3x+2=(5x-4)-5x

Group like terms:

-3x+2=(5x-5x)-4

Simplify the arithmetic:

3x+2=4

Subtract from both sides:

(-3x+2)-2=-4-2

Simplify the arithmetic:

3x=42

Simplify the arithmetic:

3x=6

Divide both sides by :

(-3x)-3=-6-3

Cancel out the negatives:

3x3=-6-3

Simplify the fraction:

x=-6-3

Cancel out the negatives:

x=63

Find the greatest common factor of the numerator and denominator:

x=(2·3)(1·3)

Factor out and cancel the greatest common factor:

x=2

10 additional steps

(2x+2)=-(5x-4)

Expand the parentheses:

(2x+2)=-5x+4

Add to both sides:

(2x+2)+5x=(-5x+4)+5x

Group like terms:

(2x+5x)+2=(-5x+4)+5x

Simplify the arithmetic:

7x+2=(-5x+4)+5x

Group like terms:

7x+2=(-5x+5x)+4

Simplify the arithmetic:

7x+2=4

Subtract from both sides:

(7x+2)-2=4-2

Simplify the arithmetic:

7x=42

Simplify the arithmetic:

7x=2

Divide both sides by :

(7x)7=27

Simplify the fraction:

x=27

3. List the solutions

x=2,27
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+2|
y=|5x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.