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Solution - Absolute value equations

Exact form: x=512,116
x=\frac{5}{12} , \frac{1}{16}
Decimal form: x=0.417,0.062
x=0.417 , 0.062

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+2|=|14x3|
without the absolute value bars:

|x|=|y||2x+2|=|14x3|
x=+y(2x+2)=(14x3)
x=y(2x+2)=(14x3)
+x=y(2x+2)=(14x3)
x=y(2x+2)=(14x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+2|=|14x3|
x=+y , +x=y(2x+2)=(14x3)
x=y , x=y(2x+2)=(14x3)

2. Solve the two equations for x

11 additional steps

(2x+2)=(14x-3)

Subtract from both sides:

(2x+2)-14x=(14x-3)-14x

Group like terms:

(2x-14x)+2=(14x-3)-14x

Simplify the arithmetic:

-12x+2=(14x-3)-14x

Group like terms:

-12x+2=(14x-14x)-3

Simplify the arithmetic:

12x+2=3

Subtract from both sides:

(-12x+2)-2=-3-2

Simplify the arithmetic:

12x=32

Simplify the arithmetic:

12x=5

Divide both sides by :

(-12x)-12=-5-12

Cancel out the negatives:

12x12=-5-12

Simplify the fraction:

x=-5-12

Cancel out the negatives:

x=512

10 additional steps

(2x+2)=-(14x-3)

Expand the parentheses:

(2x+2)=-14x+3

Add to both sides:

(2x+2)+14x=(-14x+3)+14x

Group like terms:

(2x+14x)+2=(-14x+3)+14x

Simplify the arithmetic:

16x+2=(-14x+3)+14x

Group like terms:

16x+2=(-14x+14x)+3

Simplify the arithmetic:

16x+2=3

Subtract from both sides:

(16x+2)-2=3-2

Simplify the arithmetic:

16x=32

Simplify the arithmetic:

16x=1

Divide both sides by :

(16x)16=116

Simplify the fraction:

x=116

3. List the solutions

x=512,116
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+2|
y=|14x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.