Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=6,2
x=6 , -2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+12|=|4x|
without the absolute value bars:

|x|=|y||2x+12|=|4x|
x=+y(2x+12)=(4x)
x=y(2x+12)=(4x)
+x=y(2x+12)=(4x)
x=y(2x+12)=(4x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+12|=|4x|
x=+y , +x=y(2x+12)=(4x)
x=y , x=y(2x+12)=(4x)

2. Solve the two equations for x

12 additional steps

(2x+12)=4x

Subtract from both sides:

(2x+12)-4x=(4x)-4x

Group like terms:

(2x-4x)+12=(4x)-4x

Simplify the arithmetic:

-2x+12=(4x)-4x

Simplify the arithmetic:

2x+12=0

Subtract from both sides:

(-2x+12)-12=0-12

Simplify the arithmetic:

2x=012

Simplify the arithmetic:

2x=12

Divide both sides by :

(-2x)-2=-12-2

Cancel out the negatives:

2x2=-12-2

Simplify the fraction:

x=-12-2

Cancel out the negatives:

x=122

Find the greatest common factor of the numerator and denominator:

x=(6·2)(1·2)

Factor out and cancel the greatest common factor:

x=6

9 additional steps

(2x+12)=-4x

Subtract from both sides:

(2x+12)-12=(-4x)-12

Simplify the arithmetic:

2x=(-4x)-12

Add to both sides:

(2x)+4x=((-4x)-12)+4x

Simplify the arithmetic:

6x=((-4x)-12)+4x

Group like terms:

6x=(-4x+4x)-12

Simplify the arithmetic:

6x=12

Divide both sides by :

(6x)6=-126

Simplify the fraction:

x=-126

Find the greatest common factor of the numerator and denominator:

x=(-2·6)(1·6)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=6,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+12|
y=|4x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.