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Solution - Absolute value equations

Exact form: x=5,-73
x=5 , -\frac{7}{3}
Mixed number form: x=5,-213
x=5 , -2\frac{1}{3}
Decimal form: x=5,2.333
x=5 , -2.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|x+6|
without the absolute value bars:

|x|=|y||2x+1|=|x+6|
x=+y(2x+1)=(x+6)
x=y(2x+1)=(x+6)
+x=y(2x+1)=(x+6)
x=y(2x+1)=(x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|x+6|
x=+y , +x=y(2x+1)=(x+6)
x=y , x=y(2x+1)=(x+6)

2. Solve the two equations for x

7 additional steps

(2x+1)=(x+6)

Subtract from both sides:

(2x+1)-x=(x+6)-x

Group like terms:

(2x-x)+1=(x+6)-x

Simplify the arithmetic:

x+1=(x+6)-x

Group like terms:

x+1=(x-x)+6

Simplify the arithmetic:

x+1=6

Subtract from both sides:

(x+1)-1=6-1

Simplify the arithmetic:

x=61

Simplify the arithmetic:

x=5

10 additional steps

(2x+1)=-(x+6)

Expand the parentheses:

(2x+1)=-x-6

Add to both sides:

(2x+1)+x=(-x-6)+x

Group like terms:

(2x+x)+1=(-x-6)+x

Simplify the arithmetic:

3x+1=(-x-6)+x

Group like terms:

3x+1=(-x+x)-6

Simplify the arithmetic:

3x+1=6

Subtract from both sides:

(3x+1)-1=-6-1

Simplify the arithmetic:

3x=61

Simplify the arithmetic:

3x=7

Divide both sides by :

(3x)3=-73

Simplify the fraction:

x=-73

3. List the solutions

x=5,-73
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.