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Solution - Absolute value equations

Exact form: x=2,13
x=2 , \frac{1}{3}
Decimal form: x=2,0.333
x=2 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|4x3|
without the absolute value bars:

|x|=|y||2x+1|=|4x3|
x=+y(2x+1)=(4x3)
x=y(2x+1)=(4x3)
+x=y(2x+1)=(4x3)
x=y(2x+1)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|4x3|
x=+y , +x=y(2x+1)=(4x3)
x=y , x=y(2x+1)=(4x3)

2. Solve the two equations for x

13 additional steps

(2x+1)=(4x-3)

Subtract from both sides:

(2x+1)-4x=(4x-3)-4x

Group like terms:

(2x-4x)+1=(4x-3)-4x

Simplify the arithmetic:

-2x+1=(4x-3)-4x

Group like terms:

-2x+1=(4x-4x)-3

Simplify the arithmetic:

2x+1=3

Subtract from both sides:

(-2x+1)-1=-3-1

Simplify the arithmetic:

2x=31

Simplify the arithmetic:

2x=4

Divide both sides by :

(-2x)-2=-4-2

Cancel out the negatives:

2x2=-4-2

Simplify the fraction:

x=-4-2

Cancel out the negatives:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(2x+1)=-(4x-3)

Expand the parentheses:

(2x+1)=-4x+3

Add to both sides:

(2x+1)+4x=(-4x+3)+4x

Group like terms:

(2x+4x)+1=(-4x+3)+4x

Simplify the arithmetic:

6x+1=(-4x+3)+4x

Group like terms:

6x+1=(-4x+4x)+3

Simplify the arithmetic:

6x+1=3

Subtract from both sides:

(6x+1)-1=3-1

Simplify the arithmetic:

6x=31

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=26

Simplify the fraction:

x=26

Find the greatest common factor of the numerator and denominator:

x=(1·2)(3·2)

Factor out and cancel the greatest common factor:

x=13

3. List the solutions

x=2,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.