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Solution - Absolute value equations

Exact form:

x = 12, 2

x=12 , 2

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 x + 1 | = | 3 x - 11 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 x + 1 \| = \| 3 x - 11 \|$
$x = + y$	$(2 x + 1) = (3 x - 11)$
$x = - y$	$(2 x + 1) = - (3 x - 11)$
$+ x = y$	$(2 x + 1) = (3 x - 11)$
$- x = y$	$- (2 x + 1) = (3 x - 11)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 x + 1 \| = \| 3 x - 11 \|$
$x = + y$ , $+ x = y$	$(2 x + 1) = (3 x - 11)$
$x = - y$ , $- x = y$	$(2 x + 1) = - (3 x - 11)$

2. Solve the two equations for x

10 additional steps

$(2 x + 1) = (3 x - 11)$

Subtract from both sides:

$(2 x + 1) - 3 x = (3 x - 11) - 3 x$

Group like terms:

$(2 x - 3 x) + 1 = (3 x - 11) - 3 x$

Simplify the arithmetic:

$- x + 1 = (3 x - 11) - 3 x$

Group like terms:

$- x + 1 = (3 x - 3 x) - 11$

Simplify the arithmetic:

$- x + 1 = - 11$

Subtract from both sides:

$(- x + 1) - 1 = - 11 - 1$

Simplify the arithmetic:

$- x = - 11 - 1$

Simplify the arithmetic:

$- x = - 12$

Multiply both sides by :

$- x \cdot - 1 = - 12 \cdot - 1$

Remove the one(s):

$x = - 12 \cdot - 1$

Simplify the arithmetic:

$x = 12$

12 additional steps

$(2 x + 1) = - (3 x - 11)$

Expand the parentheses:

$(2 x + 1) = - 3 x + 11$

Add to both sides:

$(2 x + 1) + 3 x = (- 3 x + 11) + 3 x$

Group like terms:

$(2 x + 3 x) + 1 = (- 3 x + 11) + 3 x$

Simplify the arithmetic:

$5 x + 1 = (- 3 x + 11) + 3 x$

Group like terms:

$5 x + 1 = (- 3 x + 3 x) + 11$

Simplify the arithmetic:

$5 x + 1 = 11$

Subtract from both sides:

$(5 x + 1) - 1 = 11 - 1$

Simplify the arithmetic:

$5 x = 11 - 1$

Simplify the arithmetic:

$5 x = 10$

Divide both sides by :

$\frac{(5 x)}{5} = \frac{10}{5}$

Simplify the fraction:

$x = \frac{10}{5}$

Find the greatest common factor of the numerator and denominator:

$x = \frac{(2 \cdot 5)}{(1 \cdot 5)}$

Factor out and cancel the greatest common factor:

$x = 2$

3. List the solutions

$x = 12, 2$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 x + 1 |$
$y = | 3 x - 11 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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