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Solution - Absolute value equations

Exact form: x=35,5
x=\frac{3}{5} , 5
Decimal form: x=0.6,5
x=0.6 , 5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x+1|+|3x4|=0

Add |3x4| to both sides of the equation:

|2x+1|+|3x4||3x4|=|3x4|

Simplify the arithmetic

|2x+1|=|3x4|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|3x4|
without the absolute value bars:

|x|=|y||2x+1|=|3x4|
x=+y(2x+1)=(3x4)
x=y(2x+1)=(3x4)
+x=y(2x+1)=(3x4)
x=y(2x+1)=(3x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|3x4|
x=+y , +x=y(2x+1)=(3x4)
x=y , x=y(2x+1)=(3x4)

3. Solve the two equations for x

10 additional steps

(2x+1)=-(3x-4)

Expand the parentheses:

(2x+1)=-3x+4

Add to both sides:

(2x+1)+3x=(-3x+4)+3x

Group like terms:

(2x+3x)+1=(-3x+4)+3x

Simplify the arithmetic:

5x+1=(-3x+4)+3x

Group like terms:

5x+1=(-3x+3x)+4

Simplify the arithmetic:

5x+1=4

Subtract from both sides:

(5x+1)-1=4-1

Simplify the arithmetic:

5x=41

Simplify the arithmetic:

5x=3

Divide both sides by :

(5x)5=35

Simplify the fraction:

x=35

11 additional steps

(2x+1)=-(-(3x-4))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x+1)=3x-4

Subtract from both sides:

(2x+1)-3x=(3x-4)-3x

Group like terms:

(2x-3x)+1=(3x-4)-3x

Simplify the arithmetic:

-x+1=(3x-4)-3x

Group like terms:

-x+1=(3x-3x)-4

Simplify the arithmetic:

x+1=4

Subtract from both sides:

(-x+1)-1=-4-1

Simplify the arithmetic:

x=41

Simplify the arithmetic:

x=5

Multiply both sides by :

-x·-1=-5·-1

Remove the one(s):

x=-5·-1

Simplify the arithmetic:

x=5

4. List the solutions

x=35,5
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|3x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.