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Solution - Absolute value equations

Exact form: x=0,2
x=0 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x+1|+|3x1|=0

Add |3x1| to both sides of the equation:

|2x+1|+|3x1||3x1|=|3x1|

Simplify the arithmetic

|2x+1|=|3x1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|3x1|
without the absolute value bars:

|x|=|y||2x+1|=|3x1|
x=+y(2x+1)=(3x1)
x=y(2x+1)=(3x1)
+x=y(2x+1)=(3x1)
x=y(2x+1)=(3x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|3x1|
x=+y , +x=y(2x+1)=(3x1)
x=y , x=y(2x+1)=(3x1)

3. Solve the two equations for x

9 additional steps

(2x+1)=-(3x-1)

Expand the parentheses:

(2x+1)=-3x+1

Add to both sides:

(2x+1)+3x=(-3x+1)+3x

Group like terms:

(2x+3x)+1=(-3x+1)+3x

Simplify the arithmetic:

5x+1=(-3x+1)+3x

Group like terms:

5x+1=(-3x+3x)+1

Simplify the arithmetic:

5x+1=1

Subtract from both sides:

(5x+1)-1=1-1

Simplify the arithmetic:

5x=11

Simplify the arithmetic:

5x=0

Divide both sides by the coefficient:

x=0

11 additional steps

(2x+1)=-(-(3x-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(2x+1)=3x-1

Subtract from both sides:

(2x+1)-3x=(3x-1)-3x

Group like terms:

(2x-3x)+1=(3x-1)-3x

Simplify the arithmetic:

-x+1=(3x-1)-3x

Group like terms:

-x+1=(3x-3x)-1

Simplify the arithmetic:

x+1=1

Subtract from both sides:

(-x+1)-1=-1-1

Simplify the arithmetic:

x=11

Simplify the arithmetic:

x=2

Multiply both sides by :

-x·-1=-2·-1

Remove the one(s):

x=-2·-1

Simplify the arithmetic:

x=2

4. List the solutions

x=0,2
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|3x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.