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Solution - Absolute value equations

Exact form:

v = - \frac{3}{7}, - 1

v=-\frac{3}{7} , -1

Decimal form:

v = - 0.429, - 1

v=-0.429 , -1

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 v | = | - 5 v - 3 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 v \| = \| - 5 v - 3 \|$
$x = + y$	$(2 v) = (- 5 v - 3)$
$x = - y$	$(2 v) = - (- 5 v - 3)$
$+ x = y$	$(2 v) = (- 5 v - 3)$
$- x = y$	$- (2 v) = (- 5 v - 3)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 v \| = \| - 5 v - 3 \|$
$x = + y$ , $+ x = y$	$(2 v) = (- 5 v - 3)$
$x = - y$ , $- x = y$	$(2 v) = - (- 5 v - 3)$

2. Solve the two equations for v

5 additional steps

$2 v = (- 5 v - 3)$

Add to both sides:

$(2 v) + 5 v = (- 5 v - 3) + 5 v$

Simplify the arithmetic:

$7 v = (- 5 v - 3) + 5 v$

Group like terms:

$7 v = (- 5 v + 5 v) - 3$

Simplify the arithmetic:

$7 v = - 3$

Divide both sides by :

$\frac{(7 v)}{7} = \frac{- 3}{7}$

Simplify the fraction:

$v = \frac{- 3}{7}$

9 additional steps

$2 v = - (- 5 v - 3)$

Expand the parentheses:

$2 v = 5 v + 3$

Subtract from both sides:

$(2 v) - 5 v = (5 v + 3) - 5 v$

Simplify the arithmetic:

$- 3 v = (5 v + 3) - 5 v$

Group like terms:

$- 3 v = (5 v - 5 v) + 3$

Simplify the arithmetic:

$- 3 v = 3$

Divide both sides by :

$\frac{(- 3 v)}{- 3} = \frac{3}{- 3}$

Cancel out the negatives:

$\frac{3 v}{3} = \frac{3}{- 3}$

Simplify the fraction:

$v = \frac{3}{- 3}$

Move the negative sign from the denominator to the numerator:

$v = \frac{- 3}{3}$

Simplify the fraction:

$v = - 1$

3. List the solutions

$v = - \frac{3}{7}, - 1$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 v |$
$y = | - 5 v - 3 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for v

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for v

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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