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Solution - Absolute value equations

Exact form: u=2
u=2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2u5|=|2u3|
without the absolute value bars:

|x|=|y||2u5|=|2u3|
x=+y(2u5)=(2u3)
x=y(2u5)=(2u3)
+x=y(2u5)=(2u3)
x=y(2u5)=(2u3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2u5|=|2u3|
x=+y , +x=y(2u5)=(2u3)
x=y , x=y(2u5)=(2u3)

2. Solve the two equations for u

5 additional steps

(2u-5)=(2u-3)

Subtract from both sides:

(2u-5)-2u=(2u-3)-2u

Group like terms:

(2u-2u)-5=(2u-3)-2u

Simplify the arithmetic:

-5=(2u-3)-2u

Group like terms:

-5=(2u-2u)-3

Simplify the arithmetic:

5=3

The statement is false:

5=3

The equation is false so it has no solution.

12 additional steps

(2u-5)=-(2u-3)

Expand the parentheses:

(2u-5)=-2u+3

Add to both sides:

(2u-5)+2u=(-2u+3)+2u

Group like terms:

(2u+2u)-5=(-2u+3)+2u

Simplify the arithmetic:

4u-5=(-2u+3)+2u

Group like terms:

4u-5=(-2u+2u)+3

Simplify the arithmetic:

4u5=3

Add to both sides:

(4u-5)+5=3+5

Simplify the arithmetic:

4u=3+5

Simplify the arithmetic:

4u=8

Divide both sides by :

(4u)4=84

Simplify the fraction:

u=84

Find the greatest common factor of the numerator and denominator:

u=(2·4)(1·4)

Factor out and cancel the greatest common factor:

u=2

3. Graph

Each line represents the function of one side of the equation:
y=|2u5|
y=|2u3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.