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Solution - Absolute value equations

Exact form: u=-13,2
u=-\frac{1}{3} , 2
Decimal form: u=0.333,2
u=-0.333 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2u+3|=|4u+1|
without the absolute value bars:

|x|=|y||2u+3|=|4u+1|
x=+y(2u+3)=(4u+1)
x=y(2u+3)=(4u+1)
+x=y(2u+3)=(4u+1)
x=y(2u+3)=(4u+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2u+3|=|4u+1|
x=+y , +x=y(2u+3)=(4u+1)
x=y , x=y(2u+3)=(4u+1)

2. Solve the two equations for u

11 additional steps

(2u+3)=(-4u+1)

Add to both sides:

(2u+3)+4u=(-4u+1)+4u

Group like terms:

(2u+4u)+3=(-4u+1)+4u

Simplify the arithmetic:

6u+3=(-4u+1)+4u

Group like terms:

6u+3=(-4u+4u)+1

Simplify the arithmetic:

6u+3=1

Subtract from both sides:

(6u+3)-3=1-3

Simplify the arithmetic:

6u=13

Simplify the arithmetic:

6u=2

Divide both sides by :

(6u)6=-26

Simplify the fraction:

u=-26

Find the greatest common factor of the numerator and denominator:

u=(-1·2)(3·2)

Factor out and cancel the greatest common factor:

u=-13

14 additional steps

(2u+3)=-(-4u+1)

Expand the parentheses:

(2u+3)=4u-1

Subtract from both sides:

(2u+3)-4u=(4u-1)-4u

Group like terms:

(2u-4u)+3=(4u-1)-4u

Simplify the arithmetic:

-2u+3=(4u-1)-4u

Group like terms:

-2u+3=(4u-4u)-1

Simplify the arithmetic:

2u+3=1

Subtract from both sides:

(-2u+3)-3=-1-3

Simplify the arithmetic:

2u=13

Simplify the arithmetic:

2u=4

Divide both sides by :

(-2u)-2=-4-2

Cancel out the negatives:

2u2=-4-2

Simplify the fraction:

u=-4-2

Cancel out the negatives:

u=42

Find the greatest common factor of the numerator and denominator:

u=(2·2)(1·2)

Factor out and cancel the greatest common factor:

u=2

3. List the solutions

u=-13,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2u+3|
y=|4u+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.