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Solution - Absolute value equations

Exact form:

p = \frac{1}{2}, - 1

p=\frac{1}{2} , -1

Decimal form:

p = 0.5, - 1

p=0.5 , -1

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 p - 1 | = | - 2 p + 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 p - 1 \| = \| - 2 p + 1 \|$
$x = + y$	$(2 p - 1) = (- 2 p + 1)$
$x = - y$	$(2 p - 1) = - (- 2 p + 1)$
$+ x = y$	$(2 p - 1) = (- 2 p + 1)$
$- x = y$	$- (2 p - 1) = (- 2 p + 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 p - 1 \| = \| - 2 p + 1 \|$
$x = + y$ , $+ x = y$	$(2 p - 1) = (- 2 p + 1)$
$x = - y$ , $- x = y$	$(2 p - 1) = - (- 2 p + 1)$

2. Solve the two equations for p

11 additional steps

$(2 p - 1) = (- 2 p + 1)$

Add to both sides:

$(2 p - 1) + 2 p = (- 2 p + 1) + 2 p$

Group like terms:

$(2 p + 2 p) - 1 = (- 2 p + 1) + 2 p$

Simplify the arithmetic:

$4 p - 1 = (- 2 p + 1) + 2 p$

Group like terms:

$4 p - 1 = (- 2 p + 2 p) + 1$

Simplify the arithmetic:

$4 p - 1 = 1$

Add to both sides:

$(4 p - 1) + 1 = 1 + 1$

Simplify the arithmetic:

$4 p = 1 + 1$

Simplify the arithmetic:

$4 p = 2$

Divide both sides by :

$\frac{(4 p)}{4} = \frac{2}{4}$

Simplify the fraction:

$p = \frac{2}{4}$

Find the greatest common factor of the numerator and denominator:

$p = \frac{(1 \cdot 2)}{(2 \cdot 2)}$

Factor out and cancel the greatest common factor:

$p = \frac{1}{2}$

5 additional steps

$(2 p - 1) = - (- 2 p + 1)$

Expand the parentheses:

$(2 p - 1) = 2 p - 1$

Subtract from both sides:

$(2 p - 1) - 2 p = (2 p - 1) - 2 p$

Group like terms:

$(2 p - 2 p) - 1 = (2 p - 1) - 2 p$

Simplify the arithmetic:

$- 1 = (2 p - 1) - 2 p$

Group like terms:

$- 1 = (2 p - 2 p) - 1$

Simplify the arithmetic:

$- 1 = - 1$

3. List the solutions

$p = \frac{1}{2}, - 1$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 p - 1 |$
$y = | - 2 p + 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for p

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for p

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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