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Solution - Absolute value equations

Exact form: p=10,23
p=10 , \frac{2}{3}
Decimal form: p=10,0.667
p=10 , 0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2p+8|=4|p3|
without the absolute value bars:

|x|=|y||2p+8|=4|p3|
x=+y(2p+8)=4(p3)
x=y(2p+8)=4((p3))
+x=y(2p+8)=4(p3)
x=y(2p+8)=4(p3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2p+8|=4|p3|
x=+y , +x=y(2p+8)=4(p3)
x=y , x=y(2p+8)=4((p3))

2. Solve the two equations for p

15 additional steps

(2p+8)=4·(p-3)

Expand the parentheses:

(2p+8)=4p+4·-3

Simplify the arithmetic:

(2p+8)=4p-12

Subtract from both sides:

(2p+8)-4p=(4p-12)-4p

Group like terms:

(2p-4p)+8=(4p-12)-4p

Simplify the arithmetic:

-2p+8=(4p-12)-4p

Group like terms:

-2p+8=(4p-4p)-12

Simplify the arithmetic:

2p+8=12

Subtract from both sides:

(-2p+8)-8=-12-8

Simplify the arithmetic:

2p=128

Simplify the arithmetic:

2p=20

Divide both sides by :

(-2p)-2=-20-2

Cancel out the negatives:

2p2=-20-2

Simplify the fraction:

p=-20-2

Cancel out the negatives:

p=202

Find the greatest common factor of the numerator and denominator:

p=(10·2)(1·2)

Factor out and cancel the greatest common factor:

p=10

16 additional steps

(2p+8)=4·(-(p-3))

Expand the parentheses:

(2p+8)=4·(-p+3)

(2p+8)=4·-p+4·3

Group like terms:

(2p+8)=(4·-1)p+4·3

Multiply the coefficients:

(2p+8)=-4p+4·3

Simplify the arithmetic:

(2p+8)=-4p+12

Add to both sides:

(2p+8)+4p=(-4p+12)+4p

Group like terms:

(2p+4p)+8=(-4p+12)+4p

Simplify the arithmetic:

6p+8=(-4p+12)+4p

Group like terms:

6p+8=(-4p+4p)+12

Simplify the arithmetic:

6p+8=12

Subtract from both sides:

(6p+8)-8=12-8

Simplify the arithmetic:

6p=128

Simplify the arithmetic:

6p=4

Divide both sides by :

(6p)6=46

Simplify the fraction:

p=46

Find the greatest common factor of the numerator and denominator:

p=(2·2)(3·2)

Factor out and cancel the greatest common factor:

p=23

3. List the solutions

p=10,23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2p+8|
y=4|p3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.