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Solution - Absolute value equations

Exact form:

m = - 5, - \frac{5}{3}

m=-5 , -\frac{5}{3}

Mixed number form:

m = - 5, - 1 \frac{2}{3}

m=-5 , -1\frac{2}{3}

Decimal form:

m = - 5, - 1.667

m=-5 , -1.667

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 2 m + 5 | = | m |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 2 m + 5 \| = \| m \|$
$x = + y$	$(2 m + 5) = (m)$
$x = - y$	$(2 m + 5) = - (m)$
$+ x = y$	$(2 m + 5) = (m)$
$- x = y$	$- (2 m + 5) = (m)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 2 m + 5 \| = \| m \|$
$x = + y$ , $+ x = y$	$(2 m + 5) = (m)$
$x = - y$ , $- x = y$	$(2 m + 5) = - (m)$

2. Solve the two equations for m

6 additional steps

$(2 m + 5) = m$

Subtract from both sides:

$(2 m + 5) - m = m - m$

Group like terms:

$(2 m - m) + 5 = m - m$

Simplify the arithmetic:

$m + 5 = m - m$

Simplify the arithmetic:

$m + 5 = 0$

Subtract from both sides:

$(m + 5) - 5 = 0 - 5$

Simplify the arithmetic:

$m = 0 - 5$

Simplify the arithmetic:

$m = - 5$

8 additional steps

$(2 m + 5) = - m$

Add to both sides:

$(2 m + 5) + m = - m + m$

Group like terms:

$(2 m + m) + 5 = - m + m$

Simplify the arithmetic:

$3 m + 5 = - m + m$

Simplify the arithmetic:

$3 m + 5 = 0$

Subtract from both sides:

$(3 m + 5) - 5 = 0 - 5$

Simplify the arithmetic:

$3 m = 0 - 5$

Simplify the arithmetic:

$3 m = - 5$

Divide both sides by :

$\frac{(3 m)}{3} = \frac{- 5}{3}$

Simplify the fraction:

$m = \frac{- 5}{3}$

3. List the solutions

$m = - 5, - \frac{5}{3}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 2 m + 5 |$
$y = | m |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for m

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for m

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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