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Solution - Absolute value equations

Exact form: a=-132,16
a=-\frac{13}{2} , \frac{1}{6}
Mixed number form: a=-612,16
a=-6\frac{1}{2} , \frac{1}{6}
Decimal form: a=6.5,0.167
a=-6.5 , 0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2a7|=|4a+6|
without the absolute value bars:

|x|=|y||2a7|=|4a+6|
x=+y(2a7)=(4a+6)
x=y(2a7)=(4a+6)
+x=y(2a7)=(4a+6)
x=y(2a7)=(4a+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2a7|=|4a+6|
x=+y , +x=y(2a7)=(4a+6)
x=y , x=y(2a7)=(4a+6)

2. Solve the two equations for a

11 additional steps

(2a-7)=(4a+6)

Subtract from both sides:

(2a-7)-4a=(4a+6)-4a

Group like terms:

(2a-4a)-7=(4a+6)-4a

Simplify the arithmetic:

-2a-7=(4a+6)-4a

Group like terms:

-2a-7=(4a-4a)+6

Simplify the arithmetic:

2a7=6

Add to both sides:

(-2a-7)+7=6+7

Simplify the arithmetic:

2a=6+7

Simplify the arithmetic:

2a=13

Divide both sides by :

(-2a)-2=13-2

Cancel out the negatives:

2a2=13-2

Simplify the fraction:

a=13-2

Move the negative sign from the denominator to the numerator:

a=-132

10 additional steps

(2a-7)=-(4a+6)

Expand the parentheses:

(2a-7)=-4a-6

Add to both sides:

(2a-7)+4a=(-4a-6)+4a

Group like terms:

(2a+4a)-7=(-4a-6)+4a

Simplify the arithmetic:

6a-7=(-4a-6)+4a

Group like terms:

6a-7=(-4a+4a)-6

Simplify the arithmetic:

6a7=6

Add to both sides:

(6a-7)+7=-6+7

Simplify the arithmetic:

6a=6+7

Simplify the arithmetic:

6a=1

Divide both sides by :

(6a)6=16

Simplify the fraction:

a=16

3. List the solutions

a=-132,16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2a7|
y=|4a+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.