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Solution - Absolute value equations

Exact form: a=-3,-113
a=-3 , -\frac{11}{3}
Mixed number form: a=-3,-323
a=-3 , -3\frac{2}{3}
Decimal form: a=3,3.667
a=-3 , -3.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2a+7|=|a+4|
without the absolute value bars:

|x|=|y||2a+7|=|a+4|
x=+y(2a+7)=(a+4)
x=y(2a+7)=(a+4)
+x=y(2a+7)=(a+4)
x=y(2a+7)=(a+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2a+7|=|a+4|
x=+y , +x=y(2a+7)=(a+4)
x=y , x=y(2a+7)=(a+4)

2. Solve the two equations for a

7 additional steps

(2a+7)=(a+4)

Subtract from both sides:

(2a+7)-a=(a+4)-a

Group like terms:

(2a-a)+7=(a+4)-a

Simplify the arithmetic:

a+7=(a+4)-a

Group like terms:

a+7=(a-a)+4

Simplify the arithmetic:

a+7=4

Subtract from both sides:

(a+7)-7=4-7

Simplify the arithmetic:

a=47

Simplify the arithmetic:

a=3

10 additional steps

(2a+7)=-(a+4)

Expand the parentheses:

(2a+7)=-a-4

Add to both sides:

(2a+7)+a=(-a-4)+a

Group like terms:

(2a+a)+7=(-a-4)+a

Simplify the arithmetic:

3a+7=(-a-4)+a

Group like terms:

3a+7=(-a+a)-4

Simplify the arithmetic:

3a+7=4

Subtract from both sides:

(3a+7)-7=-4-7

Simplify the arithmetic:

3a=47

Simplify the arithmetic:

3a=11

Divide both sides by :

(3a)3=-113

Simplify the fraction:

a=-113

3. List the solutions

a=-3,-113
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2a+7|
y=|a+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.