Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: a=6,-25
a=6 , -\frac{2}{5}
Decimal form: a=6,0.4
a=6 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2a+4|=|3a2|
without the absolute value bars:

|x|=|y||2a+4|=|3a2|
x=+y(2a+4)=(3a2)
x=y(2a+4)=(3a2)
+x=y(2a+4)=(3a2)
x=y(2a+4)=(3a2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2a+4|=|3a2|
x=+y , +x=y(2a+4)=(3a2)
x=y , x=y(2a+4)=(3a2)

2. Solve the two equations for a

10 additional steps

(2a+4)=(3a-2)

Subtract from both sides:

(2a+4)-3a=(3a-2)-3a

Group like terms:

(2a-3a)+4=(3a-2)-3a

Simplify the arithmetic:

-a+4=(3a-2)-3a

Group like terms:

-a+4=(3a-3a)-2

Simplify the arithmetic:

a+4=2

Subtract from both sides:

(-a+4)-4=-2-4

Simplify the arithmetic:

a=24

Simplify the arithmetic:

a=6

Multiply both sides by :

-a·-1=-6·-1

Remove the one(s):

a=-6·-1

Simplify the arithmetic:

a=6

10 additional steps

(2a+4)=-(3a-2)

Expand the parentheses:

(2a+4)=-3a+2

Add to both sides:

(2a+4)+3a=(-3a+2)+3a

Group like terms:

(2a+3a)+4=(-3a+2)+3a

Simplify the arithmetic:

5a+4=(-3a+2)+3a

Group like terms:

5a+4=(-3a+3a)+2

Simplify the arithmetic:

5a+4=2

Subtract from both sides:

(5a+4)-4=2-4

Simplify the arithmetic:

5a=24

Simplify the arithmetic:

5a=2

Divide both sides by :

(5a)5=-25

Simplify the fraction:

a=-25

3. List the solutions

a=6,-25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2a+4|
y=|3a2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.