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Solution - Absolute value equations

Exact form: a=0,-65
a=0 , -\frac{6}{5}
Mixed number form: a=0,-115
a=0 , -1\frac{1}{5}
Decimal form: a=0,1.2
a=0 , -1.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2a+3|=3|a+1|
without the absolute value bars:

|x|=|y||2a+3|=3|a+1|
x=+y(2a+3)=3(a+1)
x=y(2a+3)=3((a+1))
+x=y(2a+3)=3(a+1)
x=y(2a+3)=3(a+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2a+3|=3|a+1|
x=+y , +x=y(2a+3)=3(a+1)
x=y , x=y(2a+3)=3((a+1))

2. Solve the two equations for a

12 additional steps

(2a+3)=3·(a+1)

Expand the parentheses:

(2a+3)=3a+3·1

Simplify the arithmetic:

(2a+3)=3a+3

Subtract from both sides:

(2a+3)-3a=(3a+3)-3a

Group like terms:

(2a-3a)+3=(3a+3)-3a

Simplify the arithmetic:

-a+3=(3a+3)-3a

Group like terms:

-a+3=(3a-3a)+3

Simplify the arithmetic:

a+3=3

Subtract from both sides:

(-a+3)-3=3-3

Simplify the arithmetic:

a=33

Simplify the arithmetic:

a=0

Multiply both sides by :

-a·-1=0·-1

Remove the one(s):

a=0·-1

Multiply by zero:

a=0

14 additional steps

(2a+3)=3·(-(a+1))

Expand the parentheses:

(2a+3)=3·(-a-1)

(2a+3)=3·-a+3·-1

Group like terms:

(2a+3)=(3·-1)a+3·-1

Multiply the coefficients:

(2a+3)=-3a+3·-1

Simplify the arithmetic:

(2a+3)=-3a-3

Add to both sides:

(2a+3)+3a=(-3a-3)+3a

Group like terms:

(2a+3a)+3=(-3a-3)+3a

Simplify the arithmetic:

5a+3=(-3a-3)+3a

Group like terms:

5a+3=(-3a+3a)-3

Simplify the arithmetic:

5a+3=3

Subtract from both sides:

(5a+3)-3=-3-3

Simplify the arithmetic:

5a=33

Simplify the arithmetic:

5a=6

Divide both sides by :

(5a)5=-65

Simplify the fraction:

a=-65

3. List the solutions

a=0,-65
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2a+3|
y=3|a+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.