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Solution - Absolute value equations

Exact form: x=0,0
x=0 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|202x|=|4x|
without the absolute value bars:

|x|=|y||202x|=|4x|
x=+y(202x)=(4x)
x=y(202x)=(4x)
+x=y(202x)=(4x)
x=y(202x)=(4x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||202x|=|4x|
x=+y , +x=y(202x)=(4x)
x=y , x=y(202x)=(4x)

2. Solve the two equations for x

3 additional steps

202x=4x

Subtract from both sides:

(202x)-4x=(4x)-4x

Simplify the arithmetic:

198x=(4x)-4x

Simplify the arithmetic:

198x=0

Divide both sides by the coefficient:

x=0

12 additional steps

202x=4x

Divide both sides by :

(202x)202=(-4x)202

Simplify the fraction:

x=(-4x)202

Simplify the fraction:

x=-2101x

Add to both sides:

x+2101·x=(-2101x)+2101x

Group the coefficients:

(1+2101)x=(-2101·x)+2101x

Convert the integer into a fraction:

(101101+2101)x=(-2101·x)+2101x

Combine the fractions:

(101+2)101·x=(-2101·x)+2101x

Combine the numerators:

103101·x=(-2101·x)+2101x

Combine the fractions:

103101·x=(-2+2)101x

Combine the numerators:

103101·x=0101x

Reduce the zero numerator:

103101x=0x

Simplify the arithmetic:

103101x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=0,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|202x|
y=|4x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.