Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=8,4
x=8 , -4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+20|=|4x+4|
without the absolute value bars:

|x|=|y||2x+20|=|4x+4|
x=+y(2x+20)=(4x+4)
x=y(2x+20)=(4x+4)
+x=y(2x+20)=(4x+4)
x=y(2x+20)=(4x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+20|=|4x+4|
x=+y , +x=y(2x+20)=(4x+4)
x=y , x=y(2x+20)=(4x+4)

2. Solve the two equations for x

13 additional steps

(2x+20)=(4x+4)

Subtract from both sides:

(2x+20)-4x=(4x+4)-4x

Group like terms:

(2x-4x)+20=(4x+4)-4x

Simplify the arithmetic:

-2x+20=(4x+4)-4x

Group like terms:

-2x+20=(4x-4x)+4

Simplify the arithmetic:

2x+20=4

Subtract from both sides:

(-2x+20)-20=4-20

Simplify the arithmetic:

2x=420

Simplify the arithmetic:

2x=16

Divide both sides by :

(-2x)-2=-16-2

Cancel out the negatives:

2x2=-16-2

Simplify the fraction:

x=-16-2

Cancel out the negatives:

x=162

Find the greatest common factor of the numerator and denominator:

x=(8·2)(1·2)

Factor out and cancel the greatest common factor:

x=8

12 additional steps

(2x+20)=-(4x+4)

Expand the parentheses:

(2x+20)=-4x-4

Add to both sides:

(2x+20)+4x=(-4x-4)+4x

Group like terms:

(2x+4x)+20=(-4x-4)+4x

Simplify the arithmetic:

6x+20=(-4x-4)+4x

Group like terms:

6x+20=(-4x+4x)-4

Simplify the arithmetic:

6x+20=4

Subtract from both sides:

(6x+20)-20=-4-20

Simplify the arithmetic:

6x=420

Simplify the arithmetic:

6x=24

Divide both sides by :

(6x)6=-246

Simplify the fraction:

x=-246

Find the greatest common factor of the numerator and denominator:

x=(-4·6)(1·6)

Factor out and cancel the greatest common factor:

x=4

3. List the solutions

x=8,4
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+20|
y=|4x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.