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Solution - Absolute value equations

Exact form: x=-310
x=-\frac{3}{10}
Decimal form: x=0.3
x=-0.3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+2|=5|x+1|
without the absolute value bars:

|x|=|y||5x+2|=5|x+1|
x=+y(5x+2)=5(x+1)
x=y(5x+2)=5((x+1))
+x=y(5x+2)=5(x+1)
x=y(5x+2)=5(x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+2|=5|x+1|
x=+y , +x=y(5x+2)=5(x+1)
x=y , x=y(5x+2)=5((x+1))

2. Solve the two equations for x

13 additional steps

(-5x+2)=5·(x+1)

Expand the parentheses:

(-5x+2)=5x+5·1

Simplify the arithmetic:

(-5x+2)=5x+5

Subtract from both sides:

(-5x+2)-5x=(5x+5)-5x

Group like terms:

(-5x-5x)+2=(5x+5)-5x

Simplify the arithmetic:

-10x+2=(5x+5)-5x

Group like terms:

-10x+2=(5x-5x)+5

Simplify the arithmetic:

10x+2=5

Subtract from both sides:

(-10x+2)-2=5-2

Simplify the arithmetic:

10x=52

Simplify the arithmetic:

10x=3

Divide both sides by :

(-10x)-10=3-10

Cancel out the negatives:

10x10=3-10

Simplify the fraction:

x=3-10

Move the negative sign from the denominator to the numerator:

x=-310

10 additional steps

(-5x+2)=5·(-(x+1))

Expand the parentheses:

(-5x+2)=5·(-x-1)

(-5x+2)=5·-x+5·-1

Group like terms:

(-5x+2)=(5·-1)x+5·-1

Multiply the coefficients:

(-5x+2)=-5x+5·-1

Simplify the arithmetic:

(-5x+2)=-5x-5

Add to both sides:

(-5x+2)+5x=(-5x-5)+5x

Group like terms:

(-5x+5x)+2=(-5x-5)+5x

Simplify the arithmetic:

2=(-5x-5)+5x

Group like terms:

2=(-5x+5x)-5

Simplify the arithmetic:

2=5

The statement is false:

2=5

The equation is false so it has no solution.

3. List the solutions

x=-310
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+2|
y=5|x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.