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Solution - Absolute value equations

Exact form: x=15,-12
x=\frac{1}{5} , -\frac{1}{2}
Decimal form: x=0.2,0.5
x=0.2 , -0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+2|=|7x|
without the absolute value bars:

|x|=|y||3x+2|=|7x|
x=+y(3x+2)=(7x)
x=y(3x+2)=(7x)
+x=y(3x+2)=(7x)
x=y(3x+2)=(7x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+2|=|7x|
x=+y , +x=y(3x+2)=(7x)
x=y , x=y(3x+2)=(7x)

2. Solve the two equations for x

12 additional steps

(-3x+2)=7x

Subtract from both sides:

(-3x+2)-7x=(7x)-7x

Group like terms:

(-3x-7x)+2=(7x)-7x

Simplify the arithmetic:

-10x+2=(7x)-7x

Simplify the arithmetic:

10x+2=0

Subtract from both sides:

(-10x+2)-2=0-2

Simplify the arithmetic:

10x=02

Simplify the arithmetic:

10x=2

Divide both sides by :

(-10x)-10=-2-10

Cancel out the negatives:

10x10=-2-10

Simplify the fraction:

x=-2-10

Cancel out the negatives:

x=210

Find the greatest common factor of the numerator and denominator:

x=(1·2)(5·2)

Factor out and cancel the greatest common factor:

x=15

9 additional steps

(-3x+2)=-7x

Subtract from both sides:

(-3x+2)-2=(-7x)-2

Simplify the arithmetic:

-3x=(-7x)-2

Add to both sides:

(-3x)+7x=((-7x)-2)+7x

Simplify the arithmetic:

4x=((-7x)-2)+7x

Group like terms:

4x=(-7x+7x)-2

Simplify the arithmetic:

4x=2

Divide both sides by :

(4x)4=-24

Simplify the fraction:

x=-24

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(2·2)

Factor out and cancel the greatest common factor:

x=-12

3. List the solutions

x=15,-12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+2|
y=|7x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.