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Solution - Absolute value equations

Exact form: x=3,-411
x=3 , -\frac{4}{11}
Decimal form: x=3,0.364
x=3 , -0.364

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|15x8|=|7x+16|
without the absolute value bars:

|x|=|y||15x8|=|7x+16|
x=+y(15x8)=(7x+16)
x=y(15x8)=(7x+16)
+x=y(15x8)=(7x+16)
x=y(15x8)=(7x+16)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||15x8|=|7x+16|
x=+y , +x=y(15x8)=(7x+16)
x=y , x=y(15x8)=(7x+16)

2. Solve the two equations for x

11 additional steps

(15x-8)=(7x+16)

Subtract from both sides:

(15x-8)-7x=(7x+16)-7x

Group like terms:

(15x-7x)-8=(7x+16)-7x

Simplify the arithmetic:

8x-8=(7x+16)-7x

Group like terms:

8x-8=(7x-7x)+16

Simplify the arithmetic:

8x8=16

Add to both sides:

(8x-8)+8=16+8

Simplify the arithmetic:

8x=16+8

Simplify the arithmetic:

8x=24

Divide both sides by :

(8x)8=248

Simplify the fraction:

x=248

Find the greatest common factor of the numerator and denominator:

x=(3·8)(1·8)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(15x-8)=-(7x+16)

Expand the parentheses:

(15x-8)=-7x-16

Add to both sides:

(15x-8)+7x=(-7x-16)+7x

Group like terms:

(15x+7x)-8=(-7x-16)+7x

Simplify the arithmetic:

22x-8=(-7x-16)+7x

Group like terms:

22x-8=(-7x+7x)-16

Simplify the arithmetic:

22x8=16

Add to both sides:

(22x-8)+8=-16+8

Simplify the arithmetic:

22x=16+8

Simplify the arithmetic:

22x=8

Divide both sides by :

(22x)22=-822

Simplify the fraction:

x=-822

Find the greatest common factor of the numerator and denominator:

x=(-4·2)(11·2)

Factor out and cancel the greatest common factor:

x=-411

3. List the solutions

x=3,-411
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|15x8|
y=|7x+16|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.