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Solution - Absolute value equations

Exact form: x=43,427
x=\frac{4}{3} , \frac{4}{27}
Mixed number form: x=113,427
x=1\frac{1}{3} , \frac{4}{27}
Decimal form: x=1.333,0.148
x=1.333 , 0.148

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|15x4|=|12x|
without the absolute value bars:

|x|=|y||15x4|=|12x|
x=+y(15x4)=(12x)
x=y(15x4)=(12x)
+x=y(15x4)=(12x)
x=y(15x4)=(12x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||15x4|=|12x|
x=+y , +x=y(15x4)=(12x)
x=y , x=y(15x4)=(12x)

2. Solve the two equations for x

8 additional steps

(15x-4)=12x

Subtract from both sides:

(15x-4)-12x=(12x)-12x

Group like terms:

(15x-12x)-4=(12x)-12x

Simplify the arithmetic:

3x-4=(12x)-12x

Simplify the arithmetic:

3x4=0

Add to both sides:

(3x-4)+4=0+4

Simplify the arithmetic:

3x=0+4

Simplify the arithmetic:

3x=4

Divide both sides by :

(3x)3=43

Simplify the fraction:

x=43

7 additional steps

(15x-4)=-12x

Add to both sides:

(15x-4)+4=(-12x)+4

Simplify the arithmetic:

15x=(-12x)+4

Add to both sides:

(15x)+12x=((-12x)+4)+12x

Simplify the arithmetic:

27x=((-12x)+4)+12x

Group like terms:

27x=(-12x+12x)+4

Simplify the arithmetic:

27x=4

Divide both sides by :

(27x)27=427

Simplify the fraction:

x=427

3. List the solutions

x=43,427
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|15x4|
y=|12x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.